The magnitude of the magnetic force per unit length on the top wire is
2×10⁻⁵ N/m
<h3>How can we calculate the magnitude of the magnetic force per unit length on the top wire ?</h3>
To calculate the magnitude of the magnetic force per unit length on the top wire, we are using the formula
F= 
Here we are given,
= magnetic permeability
= 4
×10⁻⁷ H m⁻¹
If= 12 A
d= distance from each wire to point.
=0.12m
Now we put the known values in the above equation, we get
F=
Or, F = 
Or, F= 2×10⁻⁵ N/m.
From the above calculation, we can conclude that the magnitude of the magnetic force per unit length on the top wire is 2×10⁻⁵ N/m.
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Not that we know of today, but we didn't know about dark matter until a few years ago.
Answer:
it is zero because the electric gap is zero within the material
Explanation:
In a metal you have many free electrons, and fixed charges formed by nuclei and electrons that are not free; therefore the charge carriers are the free electrons, these have the same negative charge and due to the lectrostatic force they repel each other as far as possible without leaving the material, this implies that at two points there must be the same potential because otherwise there would be a net Caesarian force accumulating charge in a part that would be eliminated by the Coulomb force.
With this we can review the statements the strap is: it is zero because the electric gap is zero within the material
Explanation:
It is given that, the volume of air is 53.28 m³. We need to convert it into scientific notation.
Any number in scientific notation can be given by :
a is real no and b is any integer
We have, V = 53.28 m³
To write it into scientific notation, shift decimal before 3 such that,
No multiply and divide by 10. So,
So, the correct option is (a).
