Answer:
The right response will be "450 volts".
Explanation:
The given values are:
R1 = 4.00 cm
R2 = 6.00 cm
q1 = +6.00 nC
q2 = −9.00 nC
As we know,
The potential difference between the two shell's difference will be:
⇒ ![\Delta V=K[(\frac{q1}{R1}+\frac{q2}{R2})-(\frac{q1}{R1} +(\frac{q2}{R2}))]](https://tex.z-dn.net/?f=%5CDelta%20V%3DK%5B%28%5Cfrac%7Bq1%7D%7BR1%7D%2B%5Cfrac%7Bq2%7D%7BR2%7D%29-%28%5Cfrac%7Bq1%7D%7BR1%7D%20%2B%28%5Cfrac%7Bq2%7D%7BR2%7D%29%29%5D)
![=K[\frac{q1}{R2}-\frac{q1}{R1} ]](https://tex.z-dn.net/?f=%3DK%5B%5Cfrac%7Bq1%7D%7BR2%7D-%5Cfrac%7Bq1%7D%7BR1%7D%20%5D)
On substituting the values, we get
Δ 
Answer:
A pipe has a length of 1.15 m.
a) Determine the frequency of the first harmonic if the pipe is open at each end. The velocity of sound in air is 343 m/s. Answer in units of Hz
b) What is the frequency of the first harmonic if the pipe is closed at one end?
Answer in units of Hz
Explanation:
The answer is a) Teres Major Muscle
An electrons transferred and compound forms
Answer:
- The magnitude of the vector
is 107.76 m
Explanation:
To find the components of the vectors we can use:

where
is the magnitude of the vector, and θ is the angle over the positive x axis.
The negative x axis is displaced 180 ° over the positive x axis, so, we can take:






Now, we can perform vector addition. Taking two vectors, the vector addition is performed:

So, for our vectors:


To find the magnitude of this vector, we can use the Pythagorean Theorem



And this is the magnitude we are looking for.