The force result in stretching the spring 10.0 centimeters is 2.5N.
<h3>
What is Hooke's law?</h3>
If a spring is stretched from its equilibrium position, then a force with magnitude proportional to the increase in length from the equilibrium length is pulling each end.
F = kx
where k is the proportionality constant called the spring constant or force constant.
Up to a point, the elongation of a spring is directly proportional to the force applied to it. Once you extend the spring more than 10.0 centimeters, however, it no longer follows that simple linear rule.
Let the spring constant be very low 0.04N/m
The force applied is
F = 10 cm / 0.04
F = 0.1 m / 0.04
F = 2.5 N
Thus, the force result in stretching the spring 10cm is 2.5 N.
Learn more about hooke's law.
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1. New moon
This is because the moon comes between the Earth and sun and this is only possible during its new moon phase.
2. Full moon
This is because the Earth comes between the Moon and the sun and the effect is only visible when there is a full moon.
3. Corona
The corona is the outer layer and is the only one visible when there is an eclipse.
Answer:
The average acceleration is 16.6 m/s² ⇒ 1st answer
Explanation:
A rocket achieves a lift-off velocity of 500.0 m/s from rest in
30.0 seconds
The given is:
→ The initial velocity = 0
→ The final velocity = 500 meters per seconds
→ The time is 30 seconds
Acceleration is the rate of change of velocity of the rocket
→ 
where a is the acceleration, v is the final velocity, u is the initial velocity
and t is the time
→ u = 0 , v = 500 m/s , t = 30 s
Substitute these values in the rule
→ 
m/s²
<em>The average acceleration is 16.6 m/s²</em>
Answer:
speed when the block had slid 3.40 m is 2.68 m/s
Explanation:
given data
distance = 6.80 m
speed = 3.80 m/s
to find out
speed when the block had slid 3.40 m
solution
we will apply here equation of motion that is
v²-u² = 2×a×s ..............1
here s is distance, a is acceleration and v is speed and u is initial speed that is 0
so put here all value in equation 1 to get a
v²-u² = 2×a×s
3.80²-0 = 2×a×6.80
a = 1.06 m/s²
so
speed when distance 3.40 m
from equation 1 put value
v²-u² = 2×a×s
v²-0 = 2×1.06×3.40
v² = 7.208
v = 2.68
so speed when the block had slid 3.40 m is 2.68 m/s
