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3 years ago

Using the linear equation 4x–3y=12, express: b x in terms of y

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

8 0

Answer:

y = [4(x-3)]/3

Step-by-step explanation:

4x = 12+3y

3y = 4x-12

y = [4(x-3)]/3

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A population of insects increases at the rate of 200 10t 13t2 what is the change in the population of insects between day 0 and

RUDIKE [14]

Answer:

762 days

Step-by-step explanation:

Given

$Rate = 200 + 10t + 13t^2$

Let the rate be R.

So the rate change with time is represented as:

$\frac{dR}{dt} = 200 +10t + 13t^2$

So:

$dR = (200 + 10t + 13t^2)\ dt$

To get the number of insects between day 0 and day 3, we need to integrate dR and set the bounds to 0 and 3

i.e.

$dR = (200 + 10t + 13t^2)\ dt$ becomes

$\int\limits^3_0 {dR} \, =\int\limits^3_0 (200 + 10t + 13t^2)\ dt$

$R =\int\limits^3_0 (200 + 10t + 13t^2)\ dt$

Integrate

$R = 200t + \frac{10t^2}{2} + \frac{13t^3}{3} [3,0]$

Solve for R by substituting 0 and 3 for t

$R = (200*3 + \frac{10*3^2}{2} + \frac{13*3^3}{3}) - ( 200*0 + \frac{10*0^2}{2} + \frac{13*0^3}{3})$

$R = (200*3 + \frac{10*9}{2} + \frac{13*27}{3}) - (0 + \frac{10}{2} + \frac{0}{3})$

$R = (200*3 + 5*9 + 13*9) - (0)$

$R = 600 + 45 + 117 - 0$

$R =762$

<em>The population of insect between the required interval is 762</em>

4 0

3 years ago

Solve for x. 1/15+x=3/10

ValentinkaMS [17]

Answer:

x=7/30

Step-by-step explanation:

3/10-1/15

7 0

3 years ago

Read 2 more answers

From an 18-pound cut of meat, Mr. Rand cuts off steaks weighting 1 pound 15 ounces, 3 1/8 pounds, and 4 1/2 pounds. He divides u

worty [1.4K]

Answer:

$\$15.60$

Step-by-step explanation:

Mr. Rand initially starts with 18 pounds of meat. After cutting steaks weighing pound 15 ounces, 3 and 1/8 pounds, and 4 and 1/2 pounds, he will have:

$18-1.9375-3.125-4.5=8.4375$ pounds of meat left (there are 16 ounces in a pound).

Since he sells patties that measure 9 ounces, convert 8.4375 pounds to ounces:

$8.4375\text{ lbs}\cdot 16\text{ oz/lb}=135\text{ oz}$

Because each patty is 9 ounces, he can make $\frac{135}{9}=15$ patties. He sells 3 of them for $3.12, meaning the price per patty is $\frac{\$ 3.12}{3}=\$1.04$ .