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erastovalidia [21]
2 years ago
8

Part B

Physics
1 answer:
Lena [83]2 years ago
8 0

The experiment was conducted in my toilet wash hand sink with a bar soap 30 centimeter away from the faucet, the number of drips record per minute is 120 drips

<h3>Control Experimentation</h3>

Data

  • Number of Drips Recorded = 20 drips per 10 seconds
  • In one minute(60 seconds), the number of drips recorded will be

Calculation for the number of drips per minute

= 20*6

= 120 drips

What is Control Experiment

Control  experiment are carried out to minimize the effects of variables other than the independent variable

Learn more about about control experiment

brainly.com/question/24708013

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It takes 20 N of force to move a box a distance of 10 m. How much work is done on the box?
PIT_PIT [208]

Answer:

Ans is 200 J

Explanation:

Given:  Force = 20N

            Distance = 10m

Work done  = Force * displacement

                    =  20 * 10

                    =  200 J

3 0
4 years ago
What happens to energy to during the formation of a soulotion
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5 0
3 years ago
*please refer to photo attached* The figure below shows a small, charged sphere, with a charge of q = +44.0 nC, that moves a dis
pishuonlain [190]

(a) The magnitude of the force is 1.32 x 10⁻⁵ N and direction of the electric force on the sphere towards the right.

(b) The work done on the sphere by the electric force as it moves from A to B is 2.5 x 10⁻⁶ J.

(c) The change of the electric potential energy as the sphere moves from A to B is 2.5 x 10⁻⁶ J.

(d) The potential difference between A and B is 56.7 V.

<h3>Electric force on the sphere</h3>

The electric force on the sphere is calculated as follows;

F = Eq

where;

  • E is electric field
  • q is the charge

F = 300 x (44 x 10⁻⁹)

F = 1.32 x 10⁻⁵ N

The direction of the force is towards the right.

<h3>Work done on the sphere</h3>

W = Fd

W = 1.32 x 10⁻⁵ N  x 0.189 m

W = 2.5 x 10⁻⁶ J

<h3>Change of the electric potential energy </h3>

The change in the electric potential energy (in J) as the sphere moves from A to B is equal to work done in moving the charge = 2.5 x 10⁻⁶ J.

<h3> Potential difference between A and B</h3>

VB − VA =  Ed

VB − VA =  300 N/C  x   0.189 m

VB − VA =  56.7 V

Thus, the magnitude of the force is 1.32 x 10⁻⁵ N and direction of the electric force on the sphere towards the right.

The work done on the sphere by the electric force as it moves from A to B is 2.5 x 10⁻⁶ J.

The change of the electric potential energy as the sphere moves from A to B is 2.5 x 10⁻⁶ J.

The potential difference between A and B is 56.7 V.

Learn more about potential difference here: brainly.com/question/9060304

#SPJ1

6 0
2 years ago
Can you please answer theese two qeastion
wel

The first one is C!

I hope the answer helped! please mark brainliest and vote 5 stars! >:)

6 0
3 years ago
Question 2 Ammonium phosphate NH43PO4 is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid
Mama L [17]

Answer:

The answer is 12.27 g (NH4)3PO4

Explanation:

Step 1: balance the chemical equation:

H3PO4 + 3NH3 → (NH4)3PO4

step 2: the molar masses of each of the reagents and products are calculated using the periodic table:

H3PO4:

3 atoms of H: 3x1=3 g/mol

1 atom of P: 1x30.97=30.97 g/mol

4 atoms of O: 4x16=64 g/mol

Molar mass=3+30.97+64=97.97 g/mol

3NH3:

3 atoms of N: 3x14=42 g/mol

9 atoms of H: 9x1=9 g/mol

Molar mass=42+9=51 g/mol

(NH4)3PO4:

3 atoms of N: 3x14=42 g/mol

12 atoms of H: 12x1=12 g/mol

1 atom of P: 1x30.97=30.97 g/mol

4 atoms of O: 4x16=64 g/mol

Molar mass=42+12+30.97+64=148.97 g/mol

we make a rule of three to calculate the amount of ammonium phosphate:

51 g NH3------------------148.97 g (NH4)3PO4

4.2 g NH3-----------------x g (NH4)3PO4

Clearing the x, we have:

x g (NH4)3PO4 = \frac{(4.2 g NH3)x(148.97 g (NH4)3PO4)}{51 g NH3}=12.27 g (NH4)3PO4

7 0
4 years ago
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