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lana [24]
3 years ago
9

QUESTION 23

Physics
1 answer:
Nutka1998 [239]3 years ago
8 0

Answer:

E = 3600 J

Explanation:

Given that,

Voltage, V = 115 V

Power of electric bulb, P = 60 W

We need to find the electric energy used in 1 minute. The electric energy use is given by :

E=P\times t\\\\E=60\ W\times 60\ s\\\\E = 3600\ J

Hence, the electrical energy is 3600 J.

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Light rays in a material with index of refrection 1.35 1.35 can undergo total internal reflection when they strike the interface
nekit [7.7K]

Answer:

1.30

Explanation:

To calculate the critical angle we have ti use the formula:

sin\theta_c=\frac{n_2}{n_1}

where theta_c is the critical angle, n1 is the index of refraction of the material where the light is totally reflected, and n2 is the refractive index of the other material.

By taking n_2 and replacing we obtain:

n_2=n_1sin\theta_c=(1.35)sin75.1\°=1.30

hope this helps!!

6 0
3 years ago
3.) An engineer is designing the runway for an airport. Of the planes that will use the airport,
scoray [572]

Answer: 704

Explanation:Vi = 0 m/s

vf = 65 m/s

a = 3 m/s2

d = ??

vf2 = vi2 + 2*a*d

(65 m/s)2 = (0 m/s)2 + 2*(3 m/s2)*d

4225 m2/s2 = (0 m/s)2 + (6 m/s2)*d

(4225 m 2/m2)/(6 m/s2) = d

d = 704 m

5 0
3 years ago
Read 2 more answers
Which object is probably composed of ice and dust?
Setler [38]

I think comets because they are small and they are composed of ice or water. Hope it helps :)

7 0
3 years ago
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The switch has been open for a long time before it is closed at t = 0. what is ustored, the total stored energy in the circuit e
Ivahew [28]
0. No time comparison.
5 0
3 years ago
Make the curvature radius 0.6 m, the refractive index 1.5, and the diameter 0.6 m. place the lamp so that the source of light is
vodka [1.7K]
We are given
r = 0.6 m
n = 1.5
D = 0.6 m, R1 = 30 cm
R2 = 120 cm

We are asked to get the focal length and the distance of the focal plane from the lens

We use the formula
1 / f = ( n - 1) (1/R1 - 1/R2)
Substituting and solving for f
1/ f = (1.5 - 1) (1/30 - 1/120)
f = 80 cm

The focal length is 80 cm and the distance of the focal plane from the lesn is 80 cm - 30 cm = 50 cm.<span />
5 0
3 years ago
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