The answer is in the attachment
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Answer:
The angle it subtend on the retina is
Explanation:
From the question we are told that
The length of the warbler is 
The distance from the binoculars is 
The magnification of the binoculars is 
Without the 8 X binoculars the angle made with the angular size of the object is mathematically represented as



Now magnification can be represented mathematically as

Where
is the angle the image of the warbler subtend on your retina when the binoculars i.e the binoculars zoom.
So

=> 

Generally the conversion to degrees can be mathematically evaluated as

Answer:
C
Explanation:
they both have to be the same for both to not move
Answer: 12.67 cm, 8 cm
Explanation:
Given
Normal distance of separation of eyes, d(n) = 6 cm
Distance of separation is your eyes, d(y) = 9.5 cm
Angle created during the jump, θ = 0.75°
To solve this, we use the formula,
θ = d/r, where
θ = angle created during the jump
d = separation between the eyes
r = distance from the object
θ = d/r
0.75 = 9.5 / r
r = 9.5 / 0.75
r = 12.67 cm
θ = d/r
0.75 = 6 / r
r = 6 / 0.75
r = 8 cm
Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye