QUESTION 23
1 answer:
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The frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.
<h3>What is a frequency?</h3>The number of waves that travel through a particular point in a given length of time is described by frequency. So, if a wave takes half a second to pass, the frequency is 2 per second.
Given that the energy of the photon is 4.56 x 10⁻¹⁹ J. Therefore, the frequency of the photon can be written as,
Hence, the frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.
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Answers:
(a)
μT
(b)
μm
(c) f =
Explanation:
Given electric field(in y direction) equation:
(a) The amplitude of electric field is
. Hence
The amplitude of magnetic field oscillations is
Where c = speed of light
Therefore,
μT (Where T is in seconds--signifies the oscillations)
(b) To find the wavelength use:
μm
(c) Since c = fλ
=> f = c/λ
Now plug-in the values
f = (3*10^8)/(0.4488*10^-6)
f =
(a)
(b)
(c) f =
Explanation:
Given electric field(in y direction) equation:
(a) The amplitude of electric field is
The amplitude of magnetic field oscillations is
Where c = speed of light
Therefore,
(b) To find the wavelength use:
(c) Since c = fλ
=> f = c/λ
Now plug-in the values
f = (3*10^8)/(0.4488*10^-6)
f =