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3 years ago

QUESTION 23

Physics

1 answer:

Nutka1998 [239]3 years ago

8 0

Answer:

E = 3600 J

Explanation:

Given that,

Voltage, V = 115 V

Power of electric bulb, P = 60 W

We need to find the electric energy used in 1 minute. The electric energy use is given by :

$E=P\times t\\\\E=60\ W\times 60\ s\\\\E = 3600\ J$

Hence, the electrical energy is 3600 J.

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Does gender affect your aerobic capacity?

alekssr [168]

To a degree yes, the mass and volume of a male is far greater than that of the opposite gender. As well as the type of aerobics , but with practice and daily aerobics activities one can become very flexible

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3 years ago

Wave motion is characterized by two velocities: the velocity with which the wave moves in the medium (e.g., air or a string) and

Sindrei [870]

Answer: a) v = ω /k, b) v = - ωAcos( kx −ωt)

Explanation:

y(x,t)=Asin(kx−ωt) defines the wave equation.

We are asked to find wave speed (v)

Recall that v = fλ

From the wave equation above,

k = 2π/ λ where k is the wave number and λ is the wavelength, λ = 2π /k

ω = 2πf where f is the frequency and ω is the angular frequency.

f = ω/ 2π.

By substituting for λ and ω into the wave speed formulae, we have that

v =( ω/ 2π) × (2π /k)

v = ω/k

y(x,t)=Asin(kx−ωt)

The first derivative of y with respect to x give the velocity (vy)

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v = dy/dt = A cos( kx −ωt) × (−ω)

v = - ωAcos( kx −ωt)

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4 years ago

In the elements square on the periodic table, the number with the greatest numerical value the

kkurt [141]

Answer:

Osmium

Explanation:

Because Osmium has the highest numberic value

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3 years ago

By what percent does the braking distance of a car decrease, when the speed of the car is reduced by 10.3 percent? Braking dista

likoan [24]

The braking distance is the distance traveled by a car experiencing a braking force until it comes to rest.

Our initial energy is solely kinetic:
$E_i = \frac{1}{2}mv^2$

And, since the car goes to rest, it is no longer in motion. It will have no kinetic energy.
$E_f = 0$

Therefore, there was work done by the braking force.

$W_B = E_f - E_i = -\frac{1}{2}mv^2$

Recall the definition of work:
$W = F\cdot \Delta x$

Or in this case, since the displacement and breaking force are antiparallel:
$W = -F_B\Delta x$

This is equivalent to the dissipation of kinetic energy:
$W = -F_B\Delta x = -\frac{1}{2}mv^2$

Now, to visualize this, let's rearrange the equation to solve for displacement.

$\Delta x =\frac{mv^2}{2F_B}$

<u>There is a direct, SQUARE relationship between necessary braking distance speed. </u>

If the speed was reduced by 10.3 percent, its new speed is only 89.7% percent of the original, so:
$\Delta x' =\frac{m(0.897v)^2}{2F_B}$

$\Delta x' = 0.8046\Delta x$

The reduction by a percentage is:
$1 - 0.8046 = 0.1954 \\\\\boxed{= 19.54\%}$

6 0

2 years ago

Two different simple harmonic oscillators have the same natural frequency (f=8.80 Hz) when they are on the surface of the Earth.

bekas [8.4K]

Answer:

8.80 Hz

Explanation:

The frequency of a loaded spring is given by

$f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$

where k and m are the spring constant and the mass of the load respectively. The values of these do not change because they are internal properties of the components of the system.

Hence, the frequency of the vertical spring mass does not change and is 8.80 Hz.

On the other hand, the frequency of the simple pendulum is affected because it is given by

$\dfrac{1}{2\pi}\sqrt{\dfrac{g}{l}}$

where g and l are acceleration due to gravity and length of the pendulum, respectively. It is thus seen that it depends on g, which changes with location. In fact, the new frequency is given by

$f_2 = 8.80\sqrt{\dfrac{1.67}{9.81}}=3.63 \text{ Hz}$

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3 years ago