1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lana [24]
3 years ago
9

QUESTION 23

Physics
1 answer:
Nutka1998 [239]3 years ago
8 0

Answer:

E = 3600 J

Explanation:

Given that,

Voltage, V = 115 V

Power of electric bulb, P = 60 W

We need to find the electric energy used in 1 minute. The electric energy use is given by :

E=P\times t\\\\E=60\ W\times 60\ s\\\\E = 3600\ J

Hence, the electrical energy is 3600 J.

You might be interested in
What are some problems associated with the introduction of an exotic species into an ecosystem?
vodomira [7]
People in public getting killed
5 0
3 years ago
Read 2 more answers
Chen is testing the friction of three surfaces. He pushes the same ball across three different surfaces with the same force and
Law Incorporation [45]

Answer:

im no proffesional

Explanation:

but i tghink you need a proffessional for this one

4 0
3 years ago
What is the frequency of a photon with an energy of 4. 56 x 10^-19 j
Sauron [17]

The frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.

<h3>What is a frequency?</h3>

The number of waves that travel through a particular point in a given length of time is described by frequency. So, if a wave takes half a second to pass, the frequency is 2 per second.

Given that the energy of the photon is 4.56 x 10⁻¹⁹ J. Therefore, the frequency of the photon can be written as,

\rm \gamma = \dfrac{E}{h} = \dfrac{4.56x10^{-19} J}{6.626 \times 10^{-34}\ Jsec^{-1}}\\\\\\\gamma  = 6.88 \times 10^{14}\ s^{-1}

Hence, the frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.

Learn more about Frequency:

brainly.com/question/5102661

#SPJ4

5 0
2 years ago
Read 2 more answers
QUESTION 1<br> 67.2 kilometers = how many decameters
den301095 [7]

Answer: the answer should be 6,720 decameters.

6 0
3 years ago
Read 2 more answers
In si units, the electric field in an electromagnetic wave is described by ey = 104 sin(1.40 107x − ωt). (a) find the amplitude
melamori03 [73]
Answers:
(a) B_o  = 0.3466μT
(b) \lambda = 0.4488μm
(c) f = 6.68 * 10^{14}Hz

Explanation:
Given electric field(in y direction) equation:
E_y = 104sin(1.40 * 10^7 x -\omega t)

(a) The amplitude of electric field is E_o = 104. Hence

The amplitude of magnetic field oscillations is B_o =  \frac{E_o}{c}
Where c = speed of light

Therefore,
B_o =  \frac{104}{3*10^8} = 0.3466μT (Where T is in seconds--signifies the oscillations)

(b) To find the wavelength use:
\frac{2 \pi }{\lambda} = 1.40 * 10^7
\lambda =  \frac{2 \pi}{1.40} * 10^{-7}
\lambda =  0.4488μm

(c) Since c = fλ
=> f = c/λ

Now plug-in the values
f = (3*10^8)/(0.4488*10^-6)
f = 6.68 * 10^{14}Hz


6 0
3 years ago
Other questions:
  • SOMEONE HELP ME!!!!!
    11·2 answers
  • Which illustration best demonstrates longitudinal waves?
    5·1 answer
  • 6. Can an object accelerate, but not speed up or slow down?<br> Explain:
    7·1 answer
  • A liquid with a density of 900kg/m 3 is stored in a pressurized, closed storage tank. The tank is cylindrical with a 10m diamete
    11·1 answer
  • A Bear moves at a speed of 8 m/s for a distance of 300 m. How long does it take the Bear to travel this distance?
    8·1 answer
  • A student performs an activity using a sheet of paper, a magnet, and a steel ball. The image shows the setup. The student observ
    14·2 answers
  • What is the drawback to using superconductors?
    11·1 answer
  • EVERYONE BE AWARE IF YOU GET SENT SOMETHING LIKE THIS (Answer is in the photo. I can only upload it to a file hosting service. l
    7·1 answer
  • Reasons for studying physics​
    11·2 answers
  • Carbon cycle diagram
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!