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2 years ago

What is the area of the equilateral triangle, rounded to the nearest tenth? 2.7 cm2 4.1 cm2 16.2 cm2 24.2 cm2

Mathematics

1 answer:

Paul [167]2 years ago

5 0

The area of the equilateral triangle with the given perimeter is 24.2cm².

Hence, option D)24.2cm² is the correct answer.

This question is incomplete, the complete question is:

An equilateral triangle has an apothem measuring 2.16 cm and a perimeter of 22.45 cm. What is the area of the equilateral triangle, rounded to the nearest tenth?

<h3>What is a triangle?</h3>

A triangle is simply a two-dimensional polygon with 3 sides and 3 interior angles.

An equilateral triangle is a triangle with all its three sides having the same length

The area of an equilateral triangle is expressed as;

A = ((√3)/4)a²

Where a is the length of the side

Perimeter of an equilateral triangle is expressed as;

P = 3a

Where a is the length of the side

Given that the perimeter of the equilateral triangle is 22.45 cm, the sides of the triangle will be;

P = 3a

22.45cm = 3a

a = 22.45cm / 3

a = 7.48cm

Now, the area of the equilateral triangle will be;

A = ((√3)/4)a²

A = ((√3)/4) × (7.48cm)²

A = 0.433 × 55.9504cm²

A = 24.2cm²

The area of the equilateral triangle with the given perimeter is 24.2cm².

Hence, option D)24.2cm² is the correct answer.

Learn more about triangles here: brainly.com/question/19305981

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HELP!! PLEASE!! NEED DONE ASAP I WILL GIVE 100 POINTS AND MORE IF YOU CAN GET ALL 3 QUESTIONS DONE!! THANK YOU!! I WILL ALSO MAR

VARVARA [1.3K]

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I answered the questions but that formatting is very confusing and discourages anyone for trying to answer.

The last question is confusing. If I got it wrong, tell me. I will try to answer in the comment section then.

Step-by-step explanation:

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73°. Building A is 30 feet away, and building B is 35 feet away. Which building is taller and by approximately how many feet?

$\text{tan}\theta=\frac{h_{A}}{30} \Rightarrow h_{A}=\text{tan}73\º \cdot 30 \Rightarrow h_{A}\approx 98.12 \text{ feet}$

$\text{tan}\theta=\frac{h_{B}}{35} \Rightarrow h_{B}=\text{tan}73\º \cdot 35 \Rightarrow h_{B}\approx 114.47 \text{ feet}$

$\text{Difference} \approx 16.35$

Building B is around 16.35 feet taller than building A.

A Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = a divided by 6 and tan y° = a divided by b, what is the value of cos y°?

$\text{sin}(y)=\frac{a}{6}$

$\text{tan}(y)=\frac{a}{b}$

a is the opposite side; 6 is the hypotenuse; b is the adjacent side.

Therefore,

$\text{cos}(y)=\frac{b}{6}$

If sin f° = eight ninths and the measure of segment YW is 24 units, what is the measure of segment YX? triangle XYW in which angle W is a right angle, angle X measure f degrees, and angle Y measures d degrees.

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