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3 years ago

What solutions would you propose to a car manufacturer if its car rated poorly in a crash test? Please explain your answer.

2 answers:

6 0

You would have to go and repair the car, or make your car better at the repair shop, or just get a new one because the car is weak.

scoundrel [369]3 years ago

3 0

Answer:

fix the car better

Explanation:

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For each of the experiments described below, design a table to record the results.

Fiesta28 [93]

Answer:

stupidddd guhhhhhuiijui

4 0

3 years ago

A piece of an unknown metal has a volume of 19.8 ml and a mass of 210.0 grams. The density of the metal is g/mL A piece of the s

leva [86]

Answer: The density of the metal is 10.60 g/mL and the volume occupied by 86.0 grams is 8.11 mL

Explanation:

To calculate the density of unknown metal, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$ ......(1)

Volume of unknown metal = 19.8 mL

Mass of unknown metal = 210.0 g

Putting values in equation 1, we get:

$\text{Density of unknown metal}=\frac{210.0g}{19.8mL}\\\\\text{Density of unknown metal}=10.60g/mL$

The density of the metal remains the same.

Now, calculating the volume of unknown metal, using equation 1, we get:

Density of unknown metal = 11.45 /mL

Mass of unknown metal = 86.0 g

Putting values in above equation, we get:

$10.60g/mL=\frac{86.0g}{\text{Volume of unknown metal}}\\\\\text{Volume of unknown metal}=8.11mL$

Hence, the density of the metal is 10.60 g/mL and the volume occupied by 86.0 grams is 8.11 mL

5 0

3 years ago

On which body in the Solar system would some life forms from Earth be most likely to survive?

Anon25 [30]

Answer: I would think Europa.

Explanation:

4 0

3 years ago

Read 2 more answers

What will 3.20 moles of o2 occupy at stp

ludmilkaskok [199]

The molar volume of any ideal gas at STP condition is 22.4 L

3.20 mol x 22.4L / 1 mol = 71.68 L = 71.7 L

4 0

4 years ago

At 506 K and 2.05 atm, if 6.00 grams of H2 will reacts with excess N2 what volume in liters will be produced of NH3? (R = 0.0820

Nady [450]

Answer:

90.4 liter

Explanation:

You must convert the 6.00 grams of H₂ into number of moles, and then use the stoichiometry of the reaction to find the number of moles of NH₃, which can be converted into volume using the ideal gas equation.

1. Number of moles of H₂

number of moles = mass in grams / molar mass

molar mass of H₂ = 2.016g/mol

number of moles = 6.00grams / 2.016g/mol = 2.97619mol

2. Number of moles of NH₃

i) Chemical equation:

3H₂(g) + N₂(g) → 2NH₃(g)

ii) Mole ratio:

3 mol H₂ : 2 mol NH₃

iii) Proportion:

x mol NH₃ / 2.97619mol H₂ = 3 mol NH₃ / 2 mol H₂

x = 4.4642857mol NH₃

3. Volume of NH₃

pV = nRT

V = nRT/p

V = 4.4642857mol × 0.08206 atm·liter/(K·mol) × 506K / 2.05atm

V = 90.4 liter

8 0

3 years ago