Iron accounts for about 86% of the Earth's core and Silicon is next at only 6%. Iron is by far the most abundant element in the Earth's core.
The substance should be in liquid state.
First, it takes up space in the container, which leads to that it shouldn't be a solid, because solid doesn't change its shape easily.
Second, it has a fixed volume, it's difficult to compress the substance, therefore it shouldn't be gas too, as gas can be compressed easily.
Therefore we're left with liquid. And both of these given properties fits the property of liquid.
Answer:
DNA, the proteins in hair, rubber car tires.
Step-by-step explanation:
<em>Polymers</em> are large molecules consisting of long chains of small repeating units.
DNA is a natural polymer that consists of hundreds of millions of repeating units called <em>nucleotides</em><em>.</em>
Hair protein consists of long chains of <em>amino acid</em> repeating units.
The rubber in car tires is a mixture of natural and synthetic rubber. Natural rubber consists of long chains of <em>isoprene repeating units</em>. In one type of synthetic rubber, the repeating units are <em>butadiene and styrene molecules</em>.
The <em>glass in a bottle</em> is not an organic polymer. However, some chemists consider it to be a highly cross-linked inorganic polymer of SiO₂.
<em>Ice crystals</em> are not even inorganic polymers, because the water molecules are held together only by hydrogen bonds, not covalent bonds.
Here's The Answer: <span> K = 50.2 = (2x)^2 / (0.1-x)^2
x = 0.078
so H2 eq = 0.022 M
Hope this helped! :D
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Answer:
Explanation:
Assume that you have mixed 135 mL of 0.0147 mol·L⁻¹ NiCl₂ with 190 mL of 0.250 mol·L⁻¹ NH₃.
1. Moles of Ni²⁺
2. Moles of NH₃
3. Initial concentrations after mixing
(a) Total volume
V = 135 mL + 190 mL = 325 mL
(b) [Ni²⁺]
(c) [NH₃]
3. Equilibrium concentration of Ni²⁺
The reaction will reach the same equilibrium whether it approaches from the right or left.
Assume the reaction goes to completion.
Ni²⁺ + 6NH₃ ⇌ Ni(NH₃)₆²⁺
I/mol·L⁻¹: 6.106×10⁻³ 0.1462 0
C/mol·L⁻¹: -6.106×10⁻³ 0.1462-6×6.106×10⁻³ 0
E/mol·L⁻¹: 0 0.1095 6.106×10⁻³
Then we approach equilibrium from the right.
Ni²⁺ + 6NH₃ ⇌ Ni(NH₃)₆²⁺
I/mol·L⁻¹: 0 0.1095 6.106×10⁻³
C/mol·L⁻¹: +x +6x -x
E/mol·L⁻¹: x 0.1095+6x 6.106×10⁻³-x
Kf is large, so x ≪ 6.106×10⁻³. Then