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Nutka1998 [239]
4 years ago
14

Which elements are metalloids? Check all that apply.

Chemistry
2 answers:
Finger [1]4 years ago
7 0
<h3>Answer:</h3>
  • Boron
  • Silicon
  • Tellurium
<h3>Explanation:</h3>
  • Elements in the periodic table are either metals, non-metals or metalloids.
  • Metals are elements that react by losing electron(s) to attain an octet configuration. They occupy groups I, II and III of the periodic table and the transition metals.
  • Non-metals, on the other hand, are elements that react by gaining electron(s) to attain a stable configuration. Examples include halogens and noble gases among others.
  • Metalloids are elements in the periodic table that have the properties of both metals and non-metals.
  • Other examples of metalloids are arsenic, tellurium, germanium and polonium.
Gemiola [76]4 years ago
7 0

Answer:

Boron

Silicon

Tellurium

Explanation:

edgenuity

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Fluorine is diatomic element. What is the number of molecules in 10 moles<br> of fluorine gas?
sweet-ann [11.9K]
<h2>Answer:</h2>

6 × 10²⁴ molecules F₂

<h2>General Formulas and Concepts:</h2><h3><u>Chemistry</u></h3>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3><u>Math</u></h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h2>Explanation:</h2>

<u>Step 1: Define</u>

10 mol F₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />10 \ mol \ F_2(\frac{6.022 \cdot 10^{23} \ molecues \ F_2}{1 \ mol \ F_2} ) = 6.022 × 10²⁴ molecules F₂

<u>Step 4: Check</u>

<em>We are given 1 sig fig. Follow sig fig rules and round.</em>

6.022 × 10²⁴ molecules F₂ ≈ 6 × 10²⁴ molecules F₂

5 0
3 years ago
Read 2 more answers
How does a higher heat capacity affect the amount of time it takes for an object’s temperature to change?
marshall27 [118]
<span> An object with a high specific heat would change temperature more slowly than one with low specific heat. Water, for example has a very high specific heat so it requires a lot of energy to heat it up. It also takes a while for water to cool down because it holds that heat for a long time. <3</span>
5 0
4 years ago
4 Na + O2 → 2 Na2O<br><br> 6.79 moles of O2 will react to form how many moles of Na2O?
Nataly_w [17]

Answer:

13.94moles of Na₂O

Explanation:

The balanced reaction expression is given as:

        4Na  +  O₂  →   2Na₂O

Given parameters:

Number of moles of O₂ = 6.97moles

Unknown:

Number of moles of Na₂O

Solution:

 To solve this problem;

            1 mole of O₂  will produce 2 moles of Na₂O ;

            6.97 moles of O₂ will produce 6.97 x 2  = 13.94moles of Na₂O

6 0
3 years ago
What is the concentration of a solution of HCl in which a 10.0 mL sample of acid required 50.0 mL of 0.150 M NaOH for neutraliza
puteri [66]

Answer:

The answer is 0.75M HCl

Explanation:

To calculate the concentration of 10 ml of HCl that would be required to neutralize 50.0 mL of 0.150 M NaOH, we use the formula:

To calculate the concentration of 10 ml of HCl that would be required to neutralize 50.0 mL of 0.150 M NaOH, we use the formula:

C1V1 = C2V2

C1 = concentration of acid

C2 = concentration of base

V1 = volume of acid

V2 = volume of base

From the information supplied in the question:

concentration of acid (HCl) is the unknown

volume of acid (HCl) = 10ml

concentration of base (NaOH) = 0.15M

volume of base (NaOH) = 50ml

C1 x 10ml = 0.15M x 50ml

C1 x 10 = 7.5

divide both side by 10

C1 = 0.75M

concentration of acid (HCl) is 0.75M

5 0
3 years ago
50.g of NaNO3 was dissolved in 1250 mL of water. what is the molality of the solution? [ Molar mass of NaNO3 = 85 g/mol
Viefleur [7K]

Answer:

Approximately 0.47\; \rm mol \cdot L^{-1} (note that 1\; \rm M = 1 \; \rm mol \cdot L^{-1}.)

Explanation:

The molarity of a solution gives the number of moles of solute in each unit volume of the solution. In this \rm NaNO_3 solution in water,

Let n be the number of moles of the solute in the whole solution. Let V represent the volume of that solution. The formula for the molarity c of that solution is:

\displaystyle c = \frac{n}{V}.

In this question, the volume of the solution is known to be 1250\; \rm mL. That's 1.250\; \rm L in standard units. What needs to be found is n, the number of moles of \rm NaNO_3 in that solution.

The molar mass (formula mass) of a compound gives the mass of each mole of units of this compound. For example, the molar mass of \rm NaNO_3 is 85\; \rm g \cdot mol^{-1} means that the mass of one mole of

\displaystyle n = \frac{m}{M}.

For this question,

\begin{aligned}&n\left(\mathrm{NaNO_3}\right) \\ &= \frac{m\left(\mathrm{NaNO_3}\right)}{M\left(\mathrm{NaNO_3}\right)}\\&= \frac{50\; \rm g}{85\; \rm g \cdot mol^{-1}} \\& \approx 0.588235\; \rm mol\end{aligned}.

Calculate the molarity of this solution:

\begin{aligned}c &= \frac{n}{V} \\&= \frac{0.588235\; \rm mol}{1.250\; \rm L} \\&\approx 0.47\;\rm mol \cdot L^{-1}\end{aligned}.

Note that 1\; \rm mol \cdot L^{-1} (one mole per liter solution) is the same as 1\; \rm M.

8 0
3 years ago
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