Answer:
14.43° or 0.25184 rad
Explanation:
v = Speed of sound in air = 343 m/s
f = Frequency = 1240 Hz
d = Width in doorway = 1.11 m
Wavelength is given by

In the case of Fraunhofer diffraction we have the relation

The minimum angle relative to the center line perpendicular to the doorway will someone outside the room hear no sound is 14.43° or 0.25184 rad
To develop this problem it will be necessary to apply the concepts related to the frequency of a spring mass system, for which it is necessary that its mathematical function is described as

Here,
k = Spring constant
m = Mass
Our values are given as,


Rearranging to find the spring constant we have that,




Therefore the spring constant is 1.38N/m
Answer:
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Explanation:
From the question we are told that

Generally the equation for momentum is mathematically given by

Therefore
T-Joe momentum 


B is your answer oscillating
Answer:
Explanation:
Mercury, the first planet from the Sun, endures drastic temperature changes from day to night. During the day, the planet is incredibly near to the Sun, with temperatures reaching 430°C.