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Zanzabum
3 years ago
7

How many pounds of meat does a cougar eat per day

Physics
1 answer:
Luba_88 [7]3 years ago
4 0
A large male cougar living in the Cascade Mountains kills a deer or elk every 9 to 12 days, eating up to 20 pounds at a time and burying the rest for later.Except for females with young, cougars are lone hunters that wander between places frequented by their prey, covering as much as 15 miles in a single night.Cougars rely on short bursts of speed to ambush their prey. A cougar may stalk an animal for an hour or more 

hope this helps in any way ! :)
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If the density of a diamond is 3.5 g/cm", what would be the mass of a diamond whose
alexandr1967 [171]

Answer:

Explanation:

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3 years ago
Wegener believed continents moved, but he did not know how. Identify what needed to happen before Wegener's idea about moving co
pochemuha

D. Advances in technology were needed to gather more evidence.

Explanation:

New technologies had to be developed to ascertain Wegener's claims.

The major flaw in Wegener's postulate was that the moving continents lacked a mechanism to drive them into motion.

His theory needed more scientific backing also.

  • A major leap was made when new technologies used during the second world war was deployed to investigate the ocean floor.
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Wegener brainly.com/question/5002949

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6 0
3 years ago
What structure help support plants
natka813 [3]
The cell structure that helps support plants is the cell wall. It provides a shell structure around the main cell of the plant and its layers so then it will have the adequate amount of strength that it needs. It's also one of the reasons why even non-woody plants such as herbs have the strength of support itself. 
4 0
3 years ago
Read 2 more answers
please help. Sound travels at 330 m/s. If a lightning bolt strikes the ground 5 m away from you, how long will it take for the s
Olenka [21]

Answer:

0.015 seconds

Explanation:

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3 0
2 years ago
An ice sled powered by a rocket engine starts from rest on a large frozen lake and accelerates at +44 ft/s2. After some time t1,
mash [69]

Answer:

a) t₁ = 4.76 s, t₂ = 85.2 s

b) v = 209 ft/s

Explanation:

Constant acceleration equations:

x = x₀ + v₀ t + ½ at²

v = at + v₀

where x is final position,

x₀ is initial position,

v₀ is initial velocity,

a is acceleration,

and t is time.

When the engine is on and the sled is accelerating:

x₀ = 0 ft

v₀ = 0 ft/s

a = 44 ft/s²

t = t₁

So:

x = 22 t₁²

v = 44 t₁

When the engine is off and the sled is coasting:

x = 18350 ft

x₀ = 22 t₁²

v₀ = 44 t₁

a = 0 ft/s²

t = t₂

So:

18350 = 22 t₁² + (44 t₁) t₂

Given that t₁ + t₂ = 90:

18350 = 22 t₁² + (44 t₁) (90 − t₁)

Now we can solve for t₁:

18350 = 22 t₁² + 3960 t₁ − 44 t₁²

18350 = 3960 t₁ − 22 t₁²

9175 = 1980 t₁ − 11 t₁²

11 t₁² − 1980 t₁ + 9175 = 0

Using quadratic formula:

t₁ = [ 1980 ± √(1980² - 4(11)(9175)) ] / 22

t₁ = 4.76, 175

Since t₁ can't be greater than 90, t₁ = 4.76 s.

Therefore, t₂ = 85.2 s.

And v = 44 t₁ = 209 ft/s.

3 0
3 years ago
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