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3 years ago

What is the weak nuclear force?

Physics

1 answer:

Norma-Jean [14]3 years ago

5 0

Answer:

Explanation:

1. would be the strong nuclear force.

3. would be the electromagnetic force.

4. would be gravity.

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A piano wire with mass 2.60g and length 84.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and amplit

likoan [24]

Answer:

Power will be 0.2023 watt

And when amplitude is halved then power will be 0.0505 watt

Explanation:

We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg

Length of wire l = 84 cm = 0.84 m

So mass density $\mu =\frac{m}{l}=\frac{0.0026}{0.84}=0.0031kg/m$

Tension in the wire T = 25 N

Frequency f = 120 Hz

So angular frequency $\omega =2\pi f=2\times 3.14\times 120=753.6rad/sec$

And amplitude A = 1.6 mm = 0.0016 m

We have to find the generated power

Power is given by $P=\frac{1}{2}\sqrt{\mu T}\omega ^2A^2=\frac{1}{2}\times \sqrt{0.0031\times 25}\times 753.6^2\times 0.0016^2=0.2023watt$

From the relation we can see that power $P\ \propto\ A^2$

So if amplitude is halved then power will be $\frac{1}{4}$ times

So power will be equal to $\frac{0.2023}{2}=0.0505watt$

4 0

3 years ago

The image above was taken by the spacecraft Messenger as it flew by the planet Mercury. The terrain shown in this image is typic

lorasvet [3.4K]

The answer is

C

Hope this helps

7 0

3 years ago

Derive the dimension of Power

stellarik [79]

Answer:

The dimension of power is energy divided by the time or $[ML^2T^-3]$

Explanation:

Power = $\frac {Work Done}{Time}$

We can derive Dimensions of Power from both formula.

Power = Force * Velocity

As,

Force = mass * acceleration

Therefore, Dimensions of

Force = $[M]*[LT^-2] = [MLT^-2]$

Since,

Velocity = $\frac{Length}{Time}$

Now, Dimension of

Velocity = $[LT^-1]$

We have Both Dimensions,Now we can derive Dimensions Of Power,

Power = Force * Velocity

Power = $[MLT^-2] * [LT^-1]$

Power = $[ML^2T^-3]$

7 0

3 years ago

a projectile leaves the ground with a velocity of 35 meters per second at an angle 32° what is the maximum height

Nina [5.8K]

To determine the maximum height for the projectile, we can use the timeless kinematics equation $V _{f} ^{2} -V_{i}^{2}=2a \Delta y$ and plug in what we know. For $V _{f} ^{2}$ , we know it is zero because at the highest location of flight, there is no vertical velocity. For $V _{i} ^{2}$ , we know it is $(35sin(32))^{2}$ since the vertical component is the sine of the velocity. We need to solve for $y$ , so it is left as-is. Since the only acceleration is $g$ , we can substitute -9.81 into it. Solving for the equation yields a solution of 17.55 m for $\Delta y$ .

6 0

4 years ago

2. A string with a length of 0.9m that is fixed at both ends

Lostsunrise [7]

Answer:

a.) 1.8 metre

b.) 66.67 Hz

Explanation: Given that the

Length L = 0.9m

Wavelength (λ) = 2L/n

Where n = number of harmonic

If n = 1, then

Wavelength (λ) = 2L = 2 × 0.9 = 1.8 m

b.)

If waves travel at a speed of 120m/s on this string, what is the frequency

associated with the longest wave (first harmonic)?

Given that V = 120 m/s

V = Fλ

But λ = 2L, therefore,

F = V/2L

F = 120/1.8

F = 66.67 Hz

7 0

3 years ago