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stellarik [79]
2 years ago
6

What is the weak nuclear force?

Physics
1 answer:
Norma-Jean [14]2 years ago
5 0

Answer:

2.

Explanation:

1. would be the strong nuclear force.

3. would be the electromagnetic force.

4. would be gravity.

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If a body of mass 2 kg is moving with a velocity of 30 m/s, then
Svetllana [295]

Answer:

d. 60

Explanation:

If a body of mass 2 kg is moving with a velocity of 30 m/s, then

on doubling its velocity the momentum becomes

a 30 kgm/s

b 90 kgm/s

C 120 kgm/s

d 60 kgm/s

HALPLPLPPLL

7 0
2 years ago
A flow is isentropically expanded to supersonic speeds in a convergent-divergent nozzle. The reservoir and exit pressures are 1.
Kamila [148]

Answer:

Ae/A* = 1.115

Explanation:

Let the reservoir pressure be  p_0

Let the exit  pressure be p_e

Ratio of reservoir pressure and exit pressure

\frac{p_o}{p_e} = \frac{1}{0.3143}

  = 3.182

For the above value of pressure ratio

Obtain the area ratio from the isentropic flow table

Ae/A* = 1.115

The value of pressure ratio is Ae/A* = 1.115

6 0
3 years ago
A charged box ( m = 495 g, q = + 2.50 μ C ) is placed on a frictionless incline plane. Another charged box ( Q = + 75.0 μ C ) is
Rudik [331]

Answer:

a=16.2m/s^{2}

Explanation:

From the attached file diagram, the total force acting on the charged box is the downward weight and the repulsive force acting in opposite to the weight force . Hence we can write the total force as

F=masin\alpha -\frac{kQq}{r^{2}} \\\alpha =35^{0}, m=0.495kg, r=0.61m, Q=2.5*10^{-6}, q=75.0*10^{-6}\\

When fixed,F=o

Hence

masin\alpha =\frac{kQq}{r^{2}}\\0.495kg*asin35=\frac{9*10^{9}*2.5*10^{-6}*75.0*10^{-6}}{0.61^{2}} \\0.28a=4.5351\\a=\frac{4.5351}{0.28}\\\\ a=16.2m/s^{2}

The value of the acceleration is 16.2m/s^2

7 0
2 years ago
A track athlete jumps over a hurdle. What is the equal and opposite force for the force of the athlete pushing on the ground as
Jet001 [13]

Answer: Normal Force of the ground pushing the athlete up.

Explanation: I did this on Khan Academy and got the answer right.

6 0
3 years ago
A Car is travelling at 36ft/s change to miles per hour
AVprozaik [17]
\frac{36 ft}{1 sec} x  \frac{ 1 yd}{3 ft} x  \frac{1 mile}{1760 yd} x  \frac{60 sec}{1  min} x  \frac{60 min}{1 hour} =  \frac{129,600 miles}{5,280 hours}

So, this would simplify to about 25 miles per hour

Hope this is what you were looking for!
4 0
3 years ago
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