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Alex17521 [72]
3 years ago
10

During an investigation, similar glow sticks were placed in two beakers containing water at different temperatures. A record of

the investigation is shown below:
Investigation Record
Glow Stick Beaker Water
Temperature Duration of Glow Stick in
the Beaker
A 50 °F 2 minutes
B 140 °F 2 minutes


When the glow sticks were bent, chemicals inside reacted to produce a glow. Which statement is most likely correct?
Stick A glows brighter as the rate of reaction inside it is higher.
Stick A glows brighter as the rate of reaction inside it is lower.
Stick B glows brighter as the molecules inside it move faster.
Stick B glows brighter as the molecules inside it move slower.
Chemistry
2 answers:
allochka39001 [22]3 years ago
6 0

Answer:

i got you dawg just gimme one sec i'll get to you fr g

Explanation:

s2008m [1.1K]3 years ago
4 0

Answer:

It would be C i took the test

Explanation:

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Ba(OH)2 Ba+2 + 2 OH- (dissolved in solution). Which will NOT happen to the equilibrium of this solution as H+ ions are added? H+
prohojiy [21]

Answer:

The reaction will move to the left.

Explanation:

  • For the reaction:

<em>Ba(OH)₂ = Ba²⁺ + 2OH⁻,</em>

<em>Ba(OH)₂ is dissociated to Ba²⁺ and 2OH⁻.</em>

  • If H⁺ ions are added to the equilibrium:

H⁺ will combine with OH⁻ to form water.

<em>So, the concentration of OH⁻ will decrease and the equilibrium is disturbed.</em>

<em />

<em>According to Le Châtelier's principle: </em>when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

  • So, the reaction will move to the right to suppress the effect of decreasing OH⁻ concentration.

  • The base will dissociate to form more OH⁻ and thus, the quantity of Ba(OH)₂ will decrease.

<em>So, the right choice is: the reaction will move to the left, is the choice that will not happen to the equilibrium.</em>

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