In order to find the answer you must plug in the information to the frequency equation,
![c=fv](https://tex.z-dn.net/?f=c%3Dfv)
. C is the speed of light, 3.0 x 10^8. By plugging in the information you receive a frequency of
3.0 x 10^7 hz.
Group 2 elements are the alkaline earth metals
2 C4H10 + 13 O2 → 8 CO2 + 10H2O
Given, Heat of formation of C4H10 = = -125.7 kJ/molHeat of formation of water = = -241.82 kJ/molHeat of formation of CO2 = = -393.5 kJ/mol
Thus, enthalpy of combustion = ΔH = ∑Hproducts - ∑Hreactants = 8 + 10 - 2 = (-393.5X8) + (-241.82X10) - (-125.7X2) = -5314.8 kJ/mol
This energy would result in combustion of 2 moles of butane∴ For 1 mole, energy required for combustion of butane = -5314.8/2 = -2657.4 kJ/mol
The percent yield of the reaction is equal to actual yield / theoretical yield * 100%. So for this question, the percent yield is 10.3/12.9*100%=79.8%. So the answer is c.
Answer:
There is 3 sulfur and 12 oxygen atoms