Question

What mass of ni has as many atoms as there are n atoms in 63.0 g of no2?

Answer 1

Answer : The mass of Ni is, 80.346 g

Solution :

First we have to calculate the number of moles.

$\text{Moles of }NO_2=\frac{\text{Mass of }NO_2}{\text{Molar mass of }NO_2}=\frac{63g}{46g/mole}=1.369moles$

Now we have to calculate the number of atoms of $NO_2$

As 1 moles $NO_2$ contains $6.022\times 10^{23}$ number of molecules

So, 1.369 moles $NO_2$ contains $1.369\times 6.022\times 10^{23}$ number of molecules

One $NO_2$ molecule has one nitrogen atom then $1.369\times 6.022\times 10^{23}$ number of molecules of $NO_2$ will contain $1.369\times 6.022\times 10^{23}$ number of nitrogen atoms

As per question number of Ni atoms is equal to the number of nitrogen atoms

Number of Ni atoms=$1.369\times 6.022\times 10^{23}$ atoms

Number of moles = $\frac{1.369\times 6.022\times 10^{23}}{6.022\times 10^{23}}=1.369moles$

Mass of Nickel = $Moles\times \text{Molecular mass}}$

Molecular mass of Nickel = 58.69 g/mol

Mass of nickel = $1.369mol\times 58.69g/mol=80.346grams$

Answer 2

Answer:

80.42 g

Explanation:

NO2 has molar mass equal to 46 g/mol ( 14 of N + 2x16 of O). So, for 63.0 g of NO2, the number of moles are:

n = mass/molar mass

n = 63/46

n = 1.37 moles

By Avogadro's Law, 1 mol has $6.02x10^{23}$ atoms, for any substance. So, the substances will have the same number of atoms if they had the same number of moles

Then, n of Ni is 1.37 moles.

The molar mass of Ni is 58.7 g, so:

n = mass (m)/ molar mass

1.37 = m/58.7

m = 1.37x58.7

m = 80.42 g