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3 years ago

Where are the filings located?

1 answer:

8 0

Answer: Go access the EDGAR database, go to the SEC's web site - www.sec.gov - and find the section entitled "Filings and Forms (EDGAR)." Click on "Search for Company Filings." When you get to the screen entitled "Search EDGAR Database," click on "Companies and Other Filers."

You might be interested in

Give at least two ways to know if a reaction is endothermic or exothermic

mafiozo [28]

Answer:

An exothermic reaction is a chemical reaction that releases energy by light or heat. Endothermic reaction is a chemical reaction that absorbs energy or heat from its surroundings

Explanation:

5 0

3 years ago

1. What kinds of metals are REALLY reactive? why?

Olin [163]

Answer:

1. Alkali metals (group 1)

2. halogens (Group 17)

3. noble gasses (group 18)

Explanation:

1. alkali metals only have one valence electron meaning that they really want to lose that one valence electron to get a full octet.

2. halogens have 7 valence electrons meaning that they just need to gain 1 to get a full octet.

3. Nobel gasses already have a full octet meaning that they don't want to react. (atoms only react to get a full octet)

I hope this helps. Let me know if anything is unclear.

8 0

2 years ago

How many grams of NaHCO3 are needed to prepare 250 mL of 0.50 M<br> NaHCO3?

forsale [732]

Answer:

10.5g

Explanation:

First, let us calculate the number of mole of NaHCO3 present in the solution. This is illustrated below:

Volume = 250mL = 250/1000 = 0.25L

Molarity = 0.5M

Mole =?

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.5 x 0.25

Mole = 0.125 mole

Now, we shall be converting 0.125 mole of NaHCO3 to grams to obtain the desired result. This can be achieved by doing the following:

Molar Mass of NaHCO3 = 23 + 1 + 12 +(16x3) = 23 + 1 +12 +48 = 84g/mol

Number of mole of NaHCO3 = 0.125 mole

Mass of NaHCO3 =?

Mass = number of mole x molar Mass

Mass of NaHCO3 = 0.125 x 84

Mass of NaHCO3 = 10.5g

Therefore, 10.5g of NaHCO3 is needed.

6 0

2 years ago

What is the estimated density of the table tennis ball? Record your answer to the nearest hundredth. g/cm3 What is the estimated

andre [41]

Answer: Tennis ball 0.07, Golf ball 1.37

Explanation: just had this question

8 0

2 years ago

Read 2 more answers

Assuming an efficiency of 30.80%, calculate the actual yield of magnesium nitrate formed from 147.4g of magnesium and excess cop

Reil [10]

Answer:

The answer to your question is 280 g of Mg(NO₃)₂

Explanation:

Data

Efficiency = 30.80 %

Mg(NO₃)₂ = ?

Magnesium = 147.4 g

Copper (II) nitrate = excess

Balanced Reaction

Mg + Cu(NO₃)₂ ⇒ Mg(NO₃)₂ + Cu

Reactants Elements Products

1 Mg 1

1 Cu 1

2 N 2

6 O 6

Process

1.- Calculate the theoretical yield

Molecular weight Mg = 24

Molecular weight Mg(NO₃)₂ = 24 + (14 x 2) + (16 x 6)

= 24 + 28 + 96

= 148 g

24 g of Mg -------------------- 148 g of Mg(NO₃)₂

147.4 g of Mg ------------------- x

x = (147.4 x 148) / 24

x = 908.96 g of Mg(NO₃)₂

2.- Calculate the Actual yield

yield percent = $\frac{actual yield}{theoretical yield}$

Solve for actual yield

Actual yield = Yield percent x Theoretical yield

Substitution

Actual yield = $\frac{30.8}{100}$ x 908.96

Actual yield = 279.95 ≈ 280g

4 0

3 years ago