Question

When .080 moles of propane burn at STP, what volume of carbon dioxide is produced?

Answer 1

Taking into account the reaction stoichiometry and the definition of STP, 5.4 L of carbon dioxide is produced.

Reaction stoichiometry

In first place, the balanced reaction is:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

• C₃H₈: 1 mole
• O₂: 5 moles
• CO₂: 3 moles
• H₂O: 4 moles

Moles of CO₂ formed

The following rule of three can be applied: if by reaction stoichiometry 1 mole of C₃H₈ form 3 moles of CO₂, 0.080 moles of C₃H₈ form how many moles of CO₂?

$amount of moles of CO_{2} =\frac{0.080 moles of C_{3} H_{8}x3 moles of CO_{2} }{1 mole of C_{3} H_{8} }$

amount of moles of CO₂= 0.24 moles

Definition of STP condition

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

Volume of CO₂ produced

You can apply the following rule of three: If by definition of STP 1 mole of CO₂ occupies 22.4 L, 0.24 moles of CO₂ how much volume does it occupy?

$volume of CO_{2} =\frac{0.24 molesx22.4 L}{1 mole}$

volume of CO₂= 5.376 L ≅ 5.4 L

Finally, 5.4 L of carbon dioxide is produced.

Learn more about

the reaction stoichiometry:

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STP conditions:

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