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Natalija [7]
3 years ago
10

The rate of reaction was measured during a chemical reaction. After the first 3 seconds, the rate of reaction was 1.8 x10-6 M/s.

Which of the following would you expect
after another 3 seconds?
The rate would be higher, and the concentration of reactants would be lower.
The rate would be higher, and the concentration of reactants would be higher.
The rate would be lower, and the concentration of reactants would be lower
The rate would be lower, and the concentration of reactants would be higher.
Chemistry
1 answer:
avanturin [10]3 years ago
8 0

Answer:

The rate would be lower and the concentration of reactants would be lower.

Explanation:

The rate of a chemical reaction depends on the rate constant and the concentration of reactants.

For Ex:

For a reaction experimentally given by A + B ----> C + D

Rate = k[A][B]

where k is the rate constant

          [A] = concentration of reactant A

          [B] = concentration of reactant B

As the reaction proceeds,the concentration of reactant decrease and concentration of products increase.Rate constant k depends only on temperature and activation energy.Hence it will remain constant throughout the reaction assuming that reaction is carried out at constant temperature and pressure.

Hence rate will depend only on concentration of reactants and hence decrease with decrease in concentration of reactants.

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To make a 450g solution with a mass by mass concentration of 7%, how much salt and water do you need to mix?​
Yuri [45]

Explanation:

The given data is:

The mass% of a solution is 7.

Mass of solution =450g

The mass of salt required can be calculated as shown below:

mass percent =(mass of solute/mass of solution )x100\\

Substitute the given values in this formula to get the mass of solute that is salt:

mass percent =(mass of solute/mass of solution )x100\\\\7=\frac{mass of salt}{450g} x100\\=>mass of salt=7x450g /100\\mass of salt=31.5g

Mass of salt =31.5g

Mass of solvent that is water = 450g-31.5g=418.5g

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3 years ago
The reaction CO2+H2O=H2OCO3 is classified as
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In Part A, we saw that the theoretical yield of aluminum oxide is 0.700 mol . Calculate the percent yield if the actual yield of
s2008m [1.1K]

Considering the definition of percent yield, the percent yield is 76%.

<h3>Percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield=\frac{actual yield}{theorical yield}x100

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Percent yield in this case</h3>

In this case, you know:

  • actual yield= 0.532 moles
  • theorical yield= 0.700 moles

Replacing in the definition of percent yield:

percent yield=\frac{0.532 moles}{0.700 moles}x100

Solving:

<u><em>percent yield= 76%</em></u>

Finally, the percent yield is 76%.

Learn more about percent yield:

brainly.com/question/14408642

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