Answer:
We need 78.9 mL of the 19.0 M NaOH solution
Explanation:
Step 1: Data given
Molarity of the original NaOH solution = 19.0 M
Molarity of the NaOH solution we want to prepare = 3.0 M
Volume of the NaOH solution we want to prepare = 500 mL = 0.500 L
Step 2: Calculate volume of the 19.0 M NaOH solution needed
C1*V1 = C2*V2
⇒with C1 = the concentration of the original NaOH solution = 19.0 M
⇒with V1 = the volume of the original NaOH solution = TO BE DETERMINED
⇒with C2 = the concentration of the NaOH solution we want to prepare = 3.0 M
⇒with V2 = the volume of the NaOH solution we want to prepare = 500 mL = 0.500 L
19.0 M * V2 = 3.0 M * 0.500 L
V2 = (3.0 M * 0.500L) / 19.0 M
V2 = 0.0789 L
We need 0.0789 L
This is 0.0789 * 10^3 mL = 78.9 mL
We need 78.9 mL of the 19.0 M NaOH solution
22.4 molecules are in 4.48 liters of CO 2
<u>Answer:</u> The chemical equations are written below.
<u>Explanation:</u>
<u>For a:</u> Methane reacts with oxygen gas to produce carbon dioxide and water.
Combustion reaction is defined as the reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water
The chemical equation for the combustion of methane follows:

- <u>For b:</u> Butane reacts with oxygen gas to produce carbon dioxide and water.
This is also an example of combustion reaction.
The chemical equation for the combustion of butane follows:

- <u>For c:</u> An aqueous solution of sulfuric acid reacts with aqueous potassium hydroxide to produce potassium sulfate and water.
When an acid reacts with a base, it leads to the formation of salt and water. This reaction is known as neutralization reaction
The chemical equation for the reaction of potassium hydroxide and sulfuric acid follows:

Hence, the chemical equations are written above.
Answer:
A
Explanation:
A formal charge (FC) is the charge assigned to an atom in a molecule, assuming that electrons in all chemical bonds are shared equally between atoms, regardless of relative electronegativity(Wikipedia).
The formal charge on an atom in a molecule reflects the electron count associated with the atom compared to the isolated neutral atom(University of Calgary).
Looking at all the structures listed A-E for SeO2F2, only structure A minimizes the formal charges for each atom in SeO2F2.