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Lynna [10]
4 years ago
6

a mineral that has - can be split fairly easily along plains with weak atomic attraction A. streak B. Cleavage C. luster D. Hard

ness
Chemistry
2 answers:
dlinn [17]4 years ago
7 0

i believe he answer is either B. or D. I hope i helped

tatyana61 [14]4 years ago
5 0
I am going to have to say C. luster if not then B. Cleavage
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Boron has two isotopes, Boron 10 which has a mass of 10.0129 amu and Boron-11 with a mass of 11.0093 amu. B-10 occurs 84.74% of
podryga [215]

The average atomic mass of Boron: 10.431 amu

<h3>Further explanation   </h3>

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.  

So Isotopes are elements that have the same Atomic Number (Proton)  

Atomic mass is the average atomic mass of all its isotopes  

In determining the mass of an atom, as a standard is the mass of 1 carbon-12 atom whose mass is 12 amu  

Mass atom X = mass isotope 1 . % + mass isotope 2.%  + ...

The average atomic mass of boron :

\tt avg~mass=0.8474\times 10.0129+0.1526\times 11.0093\\\\avg~mass=10.431~amu

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3 years ago
How many moles of methane are produced when 4.53 mol co2 reacts
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The reaction formula CH4 + 2O2 → CO2 + 2H2O shows the oxidation of 1 mole of CH4 (Methane) will yield 1 mole of CO2 (Carbon Dioxide). Since 1 mole of CH4 will weigh 12g (for the Carbon) + 4g (1g for each Hydrogen) = 16g, then 32g of CH4 will correspond to 32g / 16g/mole = 2 moles. Therefore the oxidation of 2 moles of CH4 will yield 2 moles of CO2.
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2 years ago
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When will a seed begin to germinate?
Vlada [557]
When it has sunlight and water
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3 years ago
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1. ____ is the measure of the pull of gravity on an object.
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1. weight

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4. weight

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3 years ago
The ammonia molecule NH3 has a permanent electric dipole moment equal to 1.47 D, where 1 D = 1 debye unit = 3.34 × 10-30 C-m. Ca
svetoff [14.1K]

The electric potential due to ammonia at a point away along the axis of a dipole is 1.44 \times 10^-5 V.

<u>Explanation:</u>

Given that 1 D = 1 debye unit = 3.34 × 10-30 C-m.

Given p = 1.47 D = 1.47 \times 3.34 \times 10^-30 = 4.90 \times 10^-30.

            V = 1 / (4π∈о)  \times  (p cos(θ)) / (r^2)

where p is a permanent electric dipole,

           ∈ο is permittivity,

            r is the radius from the axis of a dipole,

            V is the electric potential.

        V = 1 / (4 \times 3.14 \times 8.85 \times 10^-12)  \times (4.90 \times 10^-30 \times 1) / (55.3 \times 10^-9)^2

        V  = 1.44 \times 10^-5 V.

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3 years ago
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