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3 years ago

What subatomic particles make up the nucleus of an atom (select ALL that are in the nucleus)

Chemistry

1 answer:

Ilia_Sergeevich [38]3 years ago

3 0

3 and 4 i would think

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If a 60-g object has a volume of 30 cm3, what is its density? 2 g/cm3 0.5 cm3/g 1800 g * cm3 none of the above

jasenka [17]

Answer : The density of an object is, $2g/cm^3$

Solution : Given,

Mass of an object = 60 g

Volume of an object = $30cm^3$

Formula used :

$\text{Density of an object}=\frac{\text{Mass of an object}}{\text{Volume of an object}}$

Now put all the given values in this formula, we get the density of an object.

$\text{Density of an object}=\frac{60g}{30cm^3}=2g/cm^3$

Therefore, the density of an object is, $2g/cm^3$

6 0

3 years ago

Which of the following elements has the largest atomic radius?

Pachacha [2.7K]

Answer:

nitrogen

Explanation:

as the group number increases, the atomic radius decreases

3 0

3 years ago

Which subatomic particles have a positive charge and are located in the nucleus?

d1i1m1o1n [39]

Answer: Atomic Particles

Explanation:

toms consist of three basic particles: protons, electrons, and neutrons. The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge). The outermost regions of the atom are called electron shells and contain the electrons (negatively charged).

8 0

2 years ago

2. 27.8 mL of an unknown were added to a 50.0-mL flask that weighs 464.7 g. The total mass of the flask and the liquid is 552.4

agasfer [191]

Answer:

$d=4.24x10^{-4}\frac{lb}{in^3}$

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

$d=\frac{m}{V}$

Thus, we can find the mass of the unknown by subtracting the total mass of the liquid to the mass of the flask and the liquid:

$m=552.4g-464.7g=87.7g$

So that we are now able to calculate the density in g/mL first:

$d=\frac{87.7g}{27.8mL}=3.15g/mL$

Now, we proceed to the conversion to lb/in³ by using the following setup:

$d=3.15\frac{g}{mL}*\frac{1lb}{453.6g}*\frac{1in^3}{16.3871mL}\\\\d=4.24x10^{-4}\frac{lb}{in^3}$

Regards!

6 0

3 years ago

How do core electrons relate to the ionization energy of the atom?

Archy [21]

Answer:

For any given element, ionization energy increases as subsequent electrons are removed. For example, the energy required to remove an electron from neutral chlorine is 1251 kJ/mol. ... An even sharper increase in ionization energy is witnessed when inner-shell, or core, electrons are removed.

Hope it helps :)

6 0

3 years ago