All categories

2 years ago

the ratio of girls to boys in the sixth grade is 5:3. If there are 400 sixth graders, how many boys are there?

Mathematics

1 answer:

PilotLPTM [1.2K]2 years ago

3 0

Answer:

boys = 250

girls = 150

Step-by-step explanation:

5g = 3b eq. 1

g + b = 400 eq. 2

g = girls

b = boys

From the eq. 2

g = 400 - b

Replacing this last eq. on eq. 1:

5(400-b) = 3b

5*400 + 5*-b = 3b

2000 - 5b = 3b

2000 = 3b + 5b

2000 = 8b

2000/8 = b

250 = b

From eq. 2

g + 250 = 400

g = 400 - 250

g = 150

Check:

from eq. 1

5*150 = 3*250 = 750

You might be interested in

How do you solve 5x +x

34kurt

If you are just simplifying it it would be 6x because it's 5x plus one more x but if you are trying to find x then I have no idea

4 0

3 years ago

Read 2 more answers

2 people answer this so i can give one of you brainliest2 people answer this so i can give one of you brainliest2 people answer

Arturiano [62]

Hi, have a good day :)!!!!!

3 0

3 years ago

Read 3 more answers

Which expression is equivalent to (4^−3)^−6?<br><br>1. 4^-18<br>2. 4^18<br>3. 4^-9<br>4. 4^3

malfutka [58]

Answer:

4^18

Step-by-step explanation:

4^18 = 2^36

(4^−3)^−6? = 2^36

Please visit: https://youtu.be/_0Ft9HdNg5c

Thanks.

8 0

3 years ago

A highway on-ramp rises

Tamiku [17]

Slope = vertical length / horizontal lengthn = 15/100 = 0.15

6 0

3 years ago

Helpppp me please!!!

Semenov [28]

To find the value of q, we need to find d(-8). Put another way, we need to find the value of d(x) when x = -8

$d(x) = -\sqrt{\frac{1}{2}x+4}$

$d(-8) = -\sqrt{\frac{1}{2}(-8)+4}$

$d(-8) = -\sqrt{-4+4}$

$d(-8) = -\sqrt{0}$

$d(-8) = 0$

So this means q = 0. Note that -0 is just 0.

===========================================

The value of r will be a similar, but now we use f(x) this time.

Plug in x = 0

$f(x) = \sqrt{\frac{1}{2}x+4}$

$f(0) = \sqrt{\frac{1}{2}*0+4}$

$f(0) = \sqrt{0+4}$

$f(0) = \sqrt{4}$

$f(0) = 2$

Therefore, r = 2.

===========================================

For s, we plug x = 10 into f(x)

$f(x) = \sqrt{\frac{1}{2}x+4}$

$f(10) = \sqrt{\frac{1}{2}*10+4}$

$f(10) = \sqrt{5+4}$

$f(10) = \sqrt{9}$

$f(10) = 3$

So s = 3.

===========================================

Finally, plug x = 10 into d(x) to find the value of t

$d(x) = -\sqrt{\frac{1}{2}x+4}$

$d(10) = -\sqrt{\frac{1}{2}(10)+4}$

$d(10) = -\sqrt{5+4}$

$d(10) = -\sqrt{9}$

$d(10) = -3$

A shortcut you could have taken is to note how d(x) = -f(x), so this means

d(10) = -f(10) = -9 since f(10) = 9 was found in the previous section above.

Whichever method you use, you should find that t = -3.

===========================================

<h3>In summary:</h3><h3>q = 0</h3><h3>r = 2</h3><h3>s = 3</h3><h3>t = -3</h3>

8 0

3 years ago