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2 years ago

I can't figure it out it keeps telling me it's wrong

Mathematics

1 answer:

rjkz [21]2 years ago

3 0

Answer:

y = 1/4x

Step-by-step explanation:

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Slope -2, passes through (-4, 6)

masya89 [10]

Answer:

y = -2x-2

Step-by-step explanation:

y=mx+b

m is the slope, which you already wrote (-2)

b is the initial condition, the value of y when x equals 0.

For (-4,6), we need a value 0 for x, so we add 4, but for each x value added, we add -2 to the y value, so 4 times, 6 - 8 = -2

Hope that helps

6 0

3 years ago

What is the solution to the system of equations?

castortr0y [4]

Consider this option/solution.
P.S. The method of solution is Gauss' method.

3 0

3 years ago

Please help me with this I’ll add you and give brainliest

Shkiper50 [21]

Answer:

Step-by-step explanation:

#11 is 78 degrees

#12 is 12.81

#13 is 75.4

8 0

3 years ago

What is the solution to this rational equation? 24/x-8=4

Annette [7]

Answer:

24/x-8 = 4

Multiplying both the sides with x-8

24 = (x-8)*4

24 = 4x - 32

24 + 32 = 4x

56 = 4x

56/4 = X

14= X

4 0

2 years ago

Compute each of the following, simplifying the result into a +bi form. I look at the answer in my book it is this. But How they

OleMash [197]

<u>Step-by-step explanation:</u>

We have , to simplify a complex expression . Basically a complex expression in the form a + ib , where i = $\sqrt{-1}$ and is called iota.

Expression:

$(2+2i)^{8}$

⇒ $(2+2i)^{8}$

⇒ $2^{8}(1+i)^{8}$

We know that the mod or modulus of a complex number in the form of $a+ib$ is represented by Z and Z = $\sqrt{a^{2}+b^{2}}$ . Computing mod of $1+i$ as :

⇒ $Z = \sqrt{a^{2}+b^{2}}$

⇒ $Z = \sqrt{1^{2}+1^{2}}$

⇒ $Z = \sqrt{2}$

Putting value of $1+i$ as $Z = \sqrt{2}$ , we get:

⇒ $2^{8}(1+i)^{8}$

⇒ $2^{8}(\sqrt{2})^{8}$

⇒ $256(2^{4})$

⇒ $4096$

6 0

3 years ago