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Thepotemich [5.8K]
3 years ago
5

Please help me with this question!

Mathematics
1 answer:
Fantom [35]3 years ago
4 0
The angles 2 and 7 are congruent by the Alternate Exterior angles Theorem
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What is the value of x
Softa [21]

Answer:46

Step-by-step explanation:

180-134

5 0
3 years ago
Read 2 more answers
The prime factorization of 441 is
OLga [1]

441 is odd, so we can't divide it by 2.

Since the sum of its digits is 4+4+1=9, which is divisible by 3, we can divide 441 by 3, and we have

441\div 3=147

Which is still divisible by 3, because 1+4+7=12. We have

147\div 3=49

49 is not divisible by 3 anymore, nor by 5 (it doesn't end with 0 or 5).

It is divisible by 7 though, we have

49\div 7=7

and finally,

7\div 7=1

So, the factorization of 441 is

441=3^2\times 7^2

8 0
3 years ago
Read 2 more answers
Which sentence can represent the inequality
polet [3.4K]
C might be the correct answer try it :)
7 0
3 years ago
Solve each inequality.
Roman55 [17]

Answer:

\large\boxed{\boxed{\underline{\underline{\maltese{\pink{\pmb{\sf{\: Solution \hookrightarrow \: x > 5 }}}}}}}}

Step-by-step explanation:

\tt{x + 4 > 9}\\\\\sf{Bring \: 4 \: to \: the \: right \: side \: of \: the \: equation}.\\\\\tt{x>9-4} \\\\\sf{Subtract \: 4 \: from \: 9 \: to \: get \: 5}\\\\\boxed{\sf{x > 5}} \dashrightarrow \mathfrak{Answer}

______________

\sf{Hope \: it \: helps}\\\mathfrak{Lucazz}

4 0
3 years ago
Read 2 more answers
Can u help me with this
Nimfa-mama [501]
4b - 7 + 2b + 11 and b + 3 + b + 1 are congruent.

You add the common factors in each problem: 2b + 4 = 2b + 4
4 0
3 years ago
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