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slega [8]
2 years ago
8

The graph of y = StartAbsoluteValue x EndAbsoluteValue is transformed as shown in the graph below. Which equation represents the

transformed function? On a coordinate plane, an absolute value function is shown. The vertex of the function is at (negative 3, negative 2). It crosses the x-axis at (negative 5, 0) and (negative 1, 0) and it crosses the y-axis at (0, 1). y = StartAbsoluteValue x minus 3 EndAbsoluteValue + 2 y = StartAbsoluteValue x + 3 EndAbsoluteValue minus 2 y = StartAbsoluteValue x minus 2 EndAbsoluteValue + 3 y = StartAbsoluteValue x + 2 EndAbsoluteValue minus 3
Mathematics
2 answers:
iogann1982 [59]2 years ago
6 0

Using translation concepts, it is found that the equation of the transformed function is:

y = |x + 3| - 2.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The absolute value function is given by y = |x|, and has vertex at (0,0). After the transformations, the function has vertex (-3, -2), which means that:

  • It was shifted 3 units to the left, hence x -> x + 3.
  • It was shifted 2 units down, hence y -> y - 2.

Thus, the equation of the function is now given by:

y = |x + 3| - 2.

More can be learned about translation concepts at brainly.com/question/4521517

Mumz [18]2 years ago
4 0

Answer:y = |x + 3| - 2.

Step-by-step explanation:  B on edge

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8 0
3 years ago
Draw a net for each of the following shapes:
Margarita [4]
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4 0
3 years ago
8) through: (-3, -2), perp. to y = x – 1<br> A) y=-5x – 1 B) y=-4x – 5<br> C) y=-x – 5 D) y=-5x – 4
nexus9112 [7]

<u>Answer:</u>

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

<u>Solution:</u>

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1

We know that, <em>product of slopes of perpendicular lines is -1. </em>

So, 1 \times slope of perpendicular line =  -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

8 0
4 years ago
Three students failed their last test. If 12% of the class failed, how many students are in the class?
stellarik [79]

Answer:

There are 25 students in the class.

Step-by-step explanation:

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Divide each side by .12

x * .12 /.12 = 3/.12

x =25

There are 25 students in the class

3 0
3 years ago
Read 2 more answers
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