The answer to that question is the sum of the hours he studied for on both days, which will be 1/4 + 3/8.
However, we cannot add fractions with different denominators. In this case, it's 4 and 8.
So if we want to add them, we must make the denominators similar to each other. How to make 4 into 8? We multiply it by 2: 4 x 2 = 8.
BUT when we multiply fractions, we must multiply both the numerator and the denominator by the same number to keep its original value. In this case, if you want to multiply 4 by 2, you must also multiply 1 by 2.
=> SO to make 1/4 into y/8, we will multiply it like this (1 x 2) / (4 x 2) = 2/8
Now we can add the 2 fractions together. 2/8 + 3/8 = (2 + 3)/8 = 5/8. THIS IS YOUR ANSWER.
TL;DR: He studied 5/8 (or 0.625) hour altogether on both days.
Answer:
Only B,
Step-by-step explanation:
Because it is all addition it does not mater what order they are in,..
1,400 it will be 20 qrtly making 80 a year time 5 years
Answer:
a) 
b) 
c) 
d) 
e) The intersection between the set A and B is the element c so then we have this:

Step-by-step explanation:
We have the following space provided:
![S= [a,b,c,d,e]](https://tex.z-dn.net/?f=%20S%3D%20%5Ba%2Cb%2Cc%2Cd%2Ce%5D)
With the following probabilities:

And we define the following events:
A= [a,b,c], B=[c,d,e]
For this case we can find the individual probabilities for A and B like this:


Determine:
a. P(A)

b. P(B)

c. P(A’)
From definition of complement we have this:

d. P(AUB)
Using the total law of probability we got:

For this case
, so if we replace we got:

e. P(AnB)
The intersection between the set A and B is the element c so then we have this:

Answer:

Step-by-step explanation:
H0: µ1 – µ2 = 0
HA: µ1 – µ2 ≠ 0
We have given,
The population variances are not known and cannot be assumed equal.
The test statistic for the test is

Where,
= sample meaan of population 1
= sample mean of population 2
= sample size of population 1
= sample size of population 2
Therefore, this is the test
