When the molecule undergoes chlorination with Cl2 on heating, the hydrogen atom of the alkyl group is replaced by the chlorine atom and form chloroalkanes. The molecule X containes three types of alkyl halides, therefore three different types of chloroalkanes are formed by the replacement of hydrogem atom linked to these alkyl groups. Thus the three different types of chloroalkanes are formed - primary, secondary, and thertiary chloroalkane. Chlorination is not selective so a mixture pf products results. The products formed by the reaction of the molecule with Y with Cl2 are shown on the attached file.
Answer:
There are approximately 1.54 moles in a 275 g sample of 
.
Explanation:
To find out number of moles, fistly we have to calculate molecular mass of .
There are 2 atoms of Potassium 1 atom of Chromium and 3 atoms of oxygen in the given compound.
For molecular mass we have to add the value of mass of 2 atoms of Potassium with mass of 1 atom of Chromium and with mass of 3 atoms of oxygen.
Atomic mass of Potassium = 39
Atomic mass of Chromium = 52
Atomic mass of Oxygen = 16
Now,
Molecular mass of = 
The molecular mass of a compound is the mass of compound in one mole.
To find out the number of moles, we have to divide given mass of compound by its molecular mass.
Hence the number of moles in 275 gm of is 1.54.
First by getting moles of salicylic acid:
moles of salicylic acid = molarity * volume
= 0.02 * 0.05 L
= 0.001 mol
then moles of base KOH = molarity * volume
= 0.02 * 0.055L
= 0.0011
when total volume = 0.05 + 0.055 = 0.105 L
[salisalic acid] = moles / total volume
= 0.001 / 0.105
= 0.0095
[KOH] = moles / total volume
= 0.0011 / 0.105
= 0.01
by using H-H equation, we can get the PH:
PH = Pka + ㏒[salt/acid]
by substitution:
PH = 2.97 + ㏒[0.01 / 0.0095]
= 2.99
Answer:
Molecular oxygen and Hydrogen fluoride.
Explanation:
Definition:
Hydrogen bonding:
It is a type of dipole-dipole attraction between the hydrogen atom and more electronegative atoms.
In hydrogen bonding mostly the highly electronegative atoms are fluorine, nitrogen and oxygen.
Explanation:
In given compound such as methane CH₄ the electronegativity of carbon is 2.55 while that of hydrogen is 2.2 so there is smaller electronegativity difference that's why it can not form hydrogen bond.
In case of molecular oxygen the electronegativite atom oxygen is present. It can form hydrogen bonds with water. its electronegativity is 3.44.
In case of hydrogen fluoride the electronegativity atom fluorine is present. It will form hydrogen bonds with water. Its electronegativity is 3.98. So it is more likely to take part in hydrogen bonding.
