A peak elutes from an HPLC column 17.7 cm in length in 11.1 min. What would be the width at half‑height of the peak (in seconds)
1 answer:
Answer:
10.98 s
Explanation:
To solve this problem we first use the formula:
- H = L/N
Where:
- H = Plate height (8.68 μm, or 8.68x10⁻⁶m)
- L = Column length (17.7 cm, or 0.177 m)
- N = Number of theoretical plates (unknown)
And solve for N:
- N = 0.177 m / 8.68x10⁻⁶m
- N = 20392 plates
Then we use the formula:
- N = 5.54*
Where:
- N is the number of theoretical plates previously calculated.
- tr is the retention time (11.1 min, or 666s)
- W₀.₅ Is the width at half-height (unknown)
And solve for W₀.₅:
- W₀.₅ = 10.98 s
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