Ask question

Ask question

All categories

3 years ago

11

Can someone please help and list what each type of thing they are? (Element, Compound, Mixture of elements, Mixture of compounds

, Mixture of elements and compounds)

1 answer:

enot [183]3 years ago

5 0

1. B
2. C
3. E
4. D
5. A
6. B
7. A
8. E
9. A

Hope this helps!

You might be interested in

How many atoms are in 3.63 mol CH2Cl2?

stira [4]

308 I think? Idek tbh because I hated chemistry

8 0

2 years ago

Consider the reaction Mg₂Si(s) + 4 H₂O(ℓ) → 2 Mg(OH)₂(aq) + SiH₄(g). How many grams of silane gas (SiH₄) are formed if 25.0 g of

Neko [114]

Answer:

10.60 grams of silane gas are formed.

Explanation:

From the reaction:

Mg₂Si(s) + 4H₂O(l) → 2Mg(OH)₂(aq) + SiH₄(g)

We know that the limiting reactant is Mg₂Si, so to find the mass of SiH₄ formed we need to calculate the number of moles of Mg₂Si:

$\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}}$

Where:

m: is the mass of Mg₂Si = 25.0 g

M: is the molar mass of Mg₂Si = 76.69 g/mol

$\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}} = \frac{25.0 g}{76.69 g/mol} = 0.33 moles$

Now, the stoichiometric relation between Mg₂Si and SiH₄ is 1:1 so:

$\eta_{Mg_{2}Si} = \eta_{SiH_{4}} = 0.33 moles$

Finally, the mass of SiH₄ is:

$m_{SiH_{4}} = \eta_{SiH_{4}}*M_{SiH_{4}} = 0.33 moles*32.12 g/mol = 10.60 g$

Therefore, 10.60 grams of silane gas are formed.

I hope it helps you!

3 0

2 years ago

Please help this is due today which ones are reactive and which arent?

BARSIC [14]

Answer:

I' really don't know I'm sorry

4 0

2 years ago

Helga [31]

Metallic I’m pretty sure. :)

4 0

3 years ago

Will give brainliest!

lukranit [14]

Answer:

A.

Explanation:

melting of ice will increase water in oceans due to which water in oceans will increase and salinity will decrease. hence, melting of ice caps near the north pole affects salinity of the ocean

5 0

3 years ago