Show that the equation x^3 + x - 3 = 0 has a solution between 1 and 2

Mathematics

1 answer:

evablogger [386]1 year ago

3 0

When x = 1:

1³ + 1 - 3 = -1

When x = 2:

2³ + 2 - 3 = 7

Since f(x) = x³ + x - 3 is continuous, it follows from the intermediate value theorem that for some c in the interval (1, 2), we have f(c) = 0, since f(1) < 0 < f(2).

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