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1 year ago

Show that the equation x^3 + x - 3 = 0 has a solution between 1 and 2

Mathematics

1 answer:

evablogger [386]1 year ago

3 0

When x = 1:

1³ + 1 - 3 = -1

When x = 2:

2³ + 2 - 3 = 7

Since f(x) = x³ + x - 3 is continuous, it follows from the intermediate value theorem that for some c in the interval (1, 2), we have f(c) = 0, since f(1) < 0 < f(2).

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nirvana33 [79]

Answer:

Answer:  x is 46° 

Step-by-step explanation:

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${ \rm{x + \angle ABC + \angle ACB = 180 \degree}} \\ \\ { \rm{x + 67 \degree + 67 \degree = 180 \degree}} \\ \\ { \rm{x + 134 \degree = 180 \degree}} \\ \\ { \boxed{ \rm{x = 46 \degree}}}$

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2 years ago

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steposvetlana [31]

Answer:

Step-by-step explanation:

One good way to look at this is to graph both polynomials, as shown in the picture. A tip to help graph is to factor it out and work from there. For example, in x²+14x+48, we can gather that (x+6)(x+8) is the same thing, and it is easier to then graph it. Similarly, for x²+12x+36, we can factor it out as (x+6)² .

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attashe74 [19]

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