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Mumz [18]
2 years ago
11

(2x – y) + (2x + y) ???//

Mathematics
2 answers:
padilas [110]2 years ago
8 0

Answer: Hi!! ^^

  • Your Answer Is... 4x

Step-by-step explanation:

Simplify the expression.

Hopefully this helps <em>you !</em>

- Matthew :)

Svetach [21]2 years ago
4 0

Answer:

4x is the answer

Step-by-step explanation:

2x - y  + 2x + y \\ 4x

You might be interested in
Two soccer teams play 8 games in their season. The number of goals each team scored per game is listed below: Team X: 11, 3, 0,
Gre4nikov [31]

Answer:

C. Team Y’s scores have a lower mean value.

Step-by-step explanation:

We are given that Two soccer teams play 8 games in their season. The number of goals each team scored per game is listed below:

Team X: 11, 3, 0, 0, 2, 0, 6, 4

Team Y: 4, 2, 0, 3, 2, 1, 6, 4

Firstly, we will calculate the mean, median, range and inter-quartile range for Team X;

Mean of Team X data is given by the following formula;

        Mean, \bar X =  \frac{\sum X}{n}

                       =  \frac{11+ 3+ 0+ 0+ 2+ 0+ 6+ 4}{8}  =  \frac{26}{8}  = 3.25

So, the mean of Team X's scores is 3.25.

Now, for calculating the median; we have to arrange the data in ascending order and then observe that the number of observations (n) in the data is even or odd.

Team X: 0, 0, 0, 2, 3, 4, 6, 11

  • If n is odd, then the formula for calculating median is given by;

                         Median  =  (\frac{n+1}{2} )^{th} \text{ obs.}

  • If n is even, then the formula for calculating median is given by;

                         Median  =  \frac{(\frac{n}{2})^{th} \text{ obs.} +(\frac{n}{2}+1)^{th} \text{ obs.}  }{2}

Here, the number of observations is even, i.e. n = 8.

So, Median =  \frac{(\frac{n}{2})^{th} \text{ obs.} +(\frac{n}{2}+1)^{th} \text{ obs.}  }{2}

                   =  \frac{(\frac{8}{2})^{th} \text{ obs.} +(\frac{8}{2}+1)^{th} \text{ obs.}  }{2}

                   =  \frac{(4)^{th} \text{ obs.} +(5)^{th} \text{ obs.}  }{2}

                   =  \frac{2+3}{2}  = 2.5

So, the median of Team X's score is 2.5.

Now, the range is calculated as the difference between the highest and the lowest value in our data.

               Range = Highest value - Lowest value

                           = 11 - 0 = 11

So, the range of Team X's score is 11.

Now, the inter-quartile range of the data is given by;

        Inter-quartile range = Q_3-Q_1

Q_1=(\frac{n+1}{4} )^{th} \text{ obs.}

     =  (\frac{8+1}{4} )^{th} \text{ obs.}

     =  (2.25 )^{th} \text{ obs.}

Q_1 = 2^{nd} \text{ obs.} + 0.25[ 3^{rd} \text{ obs.} -2^{nd} \text{ obs.} ]

     =  0 + 0.25[0 - 0] = 0

Q_3=3(\frac{n+1}{4} )^{th} \text{ obs.}

     =  3(\frac{8+1}{4} )^{th} \text{ obs.}

     =  (6.75 )^{th} \text{ obs.}

Q_3 = 6^{th} \text{ obs.} + 0.75[ 7^{th} \text{ obs.} -6^{th} \text{ obs.} ]

     =  4 + 0.75[6 - 4] = 5.5

So, the inter-quartile range of Team X's score is (5.5 - 0) = 5.5.

<u>Now, we will calculate the mean, median, range and inter-quartile range for Team Y;</u>

Mean of Team Y data is given by the following formula;

        Mean, \bar Y =  \frac{\sum Y}{n}

                       =  \frac{4+ 2+ 0+ 3+ 2+ 1+ 6+ 4}{8}  =  \frac{22}{8}  = 2.75

So, the mean of Team Y's scores is 2.75.

Now, for calculating the median; we have to arrange the data in ascending order and then observe that the number of observations (n) in the data is even or odd.

Team Y: 0, 1, 2, 2, 3, 4, 4, 6

  • If n is odd, then the formula for calculating median is given by;

                         Median  =  (\frac{n+1}{2} )^{th} \text{ obs.}

  • If n is even, then the formula for calculating median is given by;

                         Median  =  \frac{(\frac{n}{2})^{th} \text{ obs.} +(\frac{n}{2}+1)^{th} \text{ obs.}  }{2}

Here, the number of observations is even, i.e. n = 8.

So, Median =  \frac{(\frac{n}{2})^{th} \text{ obs.} +(\frac{n}{2}+1)^{th} \text{ obs.}  }{2}

                   =  \frac{(\frac{8}{2})^{th} \text{ obs.} +(\frac{8}{2}+1)^{th} \text{ obs.}  }{2}

                   =  \frac{(4)^{th} \text{ obs.} +(5)^{th} \text{ obs.}  }{2}

                   =  \frac{2+3}{2}  = 2.5

So, the median of Team Y's score is 2.5.

Now, the range is calculated as the difference between the highest and the lowest value in our data.

               Range = Highest value - Lowest value

                           = 6 - 0 = 6

So, the range of Team Y's score is 6.

Now, the inter-quartile range of the data is given by;

        Inter-quartile range = Q_3-Q_1

Q_1=(\frac{n+1}{4} )^{th} \text{ obs.}

     =  (\frac{8+1}{4} )^{th} \text{ obs.}

     =  (2.25 )^{th} \text{ obs.}

Q_1 = 2^{nd} \text{ obs.} + 0.25[ 3^{rd} \text{ obs.} -2^{nd} \text{ obs.} ]

     =  1 + 0.25[2 - 1] = 1.25

Q_3=3(\frac{n+1}{4} )^{th} \text{ obs.}

     =  3(\frac{8+1}{4} )^{th} \text{ obs.}

     =  (6.75 )^{th} \text{ obs.}

Q_3 = 6^{th} \text{ obs.} + 0.75[ 7^{th} \text{ obs.} -6^{th} \text{ obs.} ]

     =  4 + 0.75[4 - 4] = 4

So, the inter-quartile range of Team Y's score is (4 - 1.25) = 2.75.

Hence, the correct statement is:

C. Team Y’s scores have a lower mean value.

4 0
3 years ago
3/6 + 1/2 what is the answer.​
Simora [160]

Answer:

reduce 3/6 to lowest terms which would be, 1/2 because 3 goes into 3 once and 3 goes into 6 twice.  

Making your equation simplified to

1/2 + 1/2

which is equal to 1

1/2 + 1/2 = 1

Step-by-step explanation:

Hope this helps! Have a fantastic day and please mark brainliest

4 0
3 years ago
Read 2 more answers
n HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you tha
Dominik [7]

Answer:

0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 17.39 ppm

Standard Deviation, σ = 4.25 ppm

Sample size = 11

We are given that the distribution of printing speed is a bell shaped distribution that is a normal distribution.

Formula:  

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

P(printing speed of the sample is greater than 17.99 ppm.)  

P(x > 17.99)  

P( x > 17.99) = P( z > \displaystyle\frac{17.99-17.39}{\frac{4.25}{\sqrt{11}}}) = P(z > 0.468229)\\\\P( z > 0.468229) = 1 - P(z < 0.468229)

Calculating the value from the standard normal table we have,

1 - 0.679 = 0321= 32.1\%\\P( x > 17.99) = 32.1\%

Thus, 0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.

8 0
3 years ago
I need help on answering this question
liubo4ka [24]

Answer:

<h2>The answer is 72°</h2>

Step-by-step explanation:

Since < RQS = < QLK and < RQS = x

< QLK is also x

< QLK and < KLM lie on a straight line

Angles on a straight line add up to 180°

To find x add < QLK and < KLM and equate them to 180°

That's

< QLK + < KLM = 180°

x + x - 36 = 180

2x = 180 - 36

2x = 144

Divide both sides by 2

We have the final answer as

<h3>x = 72°</h3>

Hope this helps you

7 0
3 years ago
Which function has the graph shown?
guapka [62]
The answer is B. y = -cos(x)
3 0
3 years ago
Read 2 more answers
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