Answer:
<u>JK is </u><u>NOT </u><u>tangent to the circle</u>
Step-by-step explanation:
A tangent of a circle is a line that intersects a circle at one and only one point. For this reason, the radius will always intersect a tangent at a 90 degree angle to prove this single point intersection. From the triangle, we can introduce the Pythagorean theorem to see if the triangle is a right triangle:
a^2 + b^2 = c^2
48^2 + 14^2 = 36^2
2304 + 196 = 1296
2500 ≠ 1296
As this is not equal, the triangle is not a right triangle and therefore states that the tangent line does not intersect the radius at 90 degrees, meaning that it does not satisfy the requirements of a tangent line.
Answer:
C. 2 1/10
Step-by-step explanation:
15 7/10-13 3/5= 15 7/10 - 13 6/10=
2 1/10
Answer:
Im pretty sure X= 5/3
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
x3−3x2+x−2
10
x414)(x3)(0)x2+6x=10
0+6x=10
(6x)+(0)=10(Combine Like Terms)
6x=10
6x=10
Step 2: Divide both sides by 6.
6x
6
=
10
6
x=
5/3
Answer:
sinθ = -5/√61
secθ = √61/6
tanθ = -5/6
Step-by-step explanation:
From the given coordinate (6, -5), x = 6 and y = -5. This shows that the point lies in the 4th quadrant. In the fourth quadrant, only cos θ is positive, both sin θ and tan θ are negative.
Let us get the value of the radius 'r' first before calculating the trigonometry identities.
Using the Pythagoras theorem;
Using SOH, CAH, TOA to get the trigonometry identities;
Given x = 6, y =5 and r = √61
Since sin θ, is negative in the fourth quadrant, 
For tanθ:
Since tan θ, is negative in the fourth quadrant, 
