If x = -3 and y = -5, what does 3x

At a hardware store, each wooden plank costs $3.57. How much do 12 planks cost?

777dan777 [17]

To find this answer, we need to multiply 3.57 by 12.
$3.57 * 12 = 42.84$
Therefore, 12 planks will cost $42.84.

5 0

3 years ago

Find the mean, median, and mode of the data, if possible. If any of these measures cannot be found or a measure does not repre

Ber [7]

Answer:

The mean cholesterol levels

= 173873.7

Step-by-step explanation:

For The mean

The mean is going to be sum of the numbers divide by the number

Mean = (130130 +145145+ 215215 +170170+ 165165 +225225+ 240240 +185185+ 130130 +132132 )/10

Mean =1738737/10

= 173873.7

For Median

Wee arrange ascending order

130130, 130130, 132132, 145145, 165165, 170170, 185185, 215215, 225225, 240240

Median = (165165+170170)/2

Median = 335335/2

Median = 167667.5

Mode = 130130

4 0

3 years ago

I need the domain range and function. With an explanation

erastovalidia [21]

<h3>Answers:</h3>

Problem 1

Domain = $-3 < x \le 3$ , interval notation (-3, 3]
Range = $-3 \le y < 3$ , interval notation [-3, 3)
Is it a function? Yes

Problem 2

Domain = $x \ge -2$ , interval notation $[-2, \infty)$
Range = All real numbers, interval notation $(-\infty, \infty)$
Is it a function? No

Problem 3

Domain = $-4 \le x < 3$ , interval notation [-4, 3)
Range = $-4 < y \le 3$ , interval notation (-4, 3]
Is it a function? Yes

Problem 4

Domain = All real numbers, interval notation $(-\infty, \infty)$
Range = $y \le 4$ , interval notation $(-\infty, 4]$
Is it a function? Yes

==================================================

Explanations:

The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore $-3 < x \le 3$ which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is $x \ge -2$ which in interval notation is $[-2, \infty)$ . The range is $(-\infty, \infty)$ to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is $y \le 4$ which is the same as saying $(-\infty, 4]$ in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.

7 0

3 years ago

Write an exponential expression: choose a number between 0 and 10 to be the base and another number between 0 and 10, different

lesya [120]

Answer:

2^4

2 * 2 * 2 * 2

Step-by-step explanation:

In the question above :

Write an exponential expression:

Base = number between 0 and 10

Exponent = number different from the base between 0 and 10

Let base = 2

Let exponent = 4

Hence, exponential expression will be

Base^exponent

2^4 (standard form)

Expanded form:

2 * 2 * 2 * 2 (multiply 2 in 4 places)

6 0

3 years ago

Can't figure it out!!

Zanzabum

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= \cfrac{1}{x} \qquad 
\begin{cases}
x_1=2\\
x_2=b
\end{cases}\implies \cfrac{f(b)-f(2)}{b-2}=-\cfrac{1}{10}
\\\\\\
\cfrac{\frac{1}{b}-\frac{1}{2}}{b-2}=-\cfrac{1}{10}\implies 
\cfrac{\frac{2-b}{2b}}{b-2}=-\cfrac{1}{10}\implies \cfrac{2-b}{2b}=-\cfrac{b-2}{10}
\\\\\\
$

$\bf \cfrac{2-b}{2b}=\cfrac{2-b}{10}\implies 20-10b=4b-2b^2\impliedby cross-multiplying
\\\\\\
2b^2-4b-10b+20=0\implies 2b^2-14b+20=0
\\\\\\
b^2-7b+10=0\implies 
(b-2)(b-5)=0\implies b=
\begin{cases}
\boxed{5}\\
2
\end{cases}$

8 0

3 years ago

If x = -3 and y = -5, what does 3x - 2y equal???