Answer:
there are a total of 20 boys and 30 girls in the choir of 50 students
Step-by-step explanation:
Scale the ratio 2:3. so that the numbers on either side sum to 50 . 2+3=5 , and 50÷5=10 , so we scale our ratio by a factor of 10 . So there are a total of 20 boys and 30 girls in the choir of 50 students
So cost=(# of items) times (Price per item)
necklace=48 bbeads and 1 charm
1 bead=0.05
charm=0.45
so we multiply
necklace=48(0.05)+1(0.45)
necklace=2.4+0.45
necklace=2.85
bracelet=25 beads and 4 charms
bracelet=25(0.05)+4(0.45)
bracelet=1.25+1.8
bracelet=3.05
necklace=$2.85
bracelet=$3.05
Average rate of change: r=[f(b)-f(a)]/(b-a)
r=-60→[f(b)-f(a)]/(b-a)=-60
b=5; f(b)=-213; a=1; f(a)=27
(-213-27)/(5-1)=(-240)/4=-60
Answer: The <span>two points in the table which create an interval with an average rate of change of -60 are:
x f(x)
1 27
5 -213</span>
Answer:
Yes she made an error. Explanation is below.
Step-by-step explanation:
Let the sample space for a six sided number cube be S
Let the event of a number getting greater than two be B
To find:
the probability of complement of B that is
p(~B) = ?
Solution"
First we need to solve probability for number getting greater than two
Now substituting the values we get
but we need complement of B so
P(complement of rolling a number greater than two) = 
I don’t know got a message but she’s like actually i
