Solve for points. identify the vertex and indicate whether it is max or min.
1 answer:
Answer:
min at (3, 0 )
Step-by-step explanation:
given a quadratic in standard form
y = ax² + bx + c ( a ≠ 0 )
then the x- coordinate of the vertex is
= -
y = (x - 3)² = x² - 6x + 9 ← in standard form
with a = 1 and b = - 6 , then
= -
= 3
substitute x = 3 into the equation for corresponding value of y
y = (3 - 3)² = 0² = 0
vertex = (3, 0 )
• if a > 0 then vertex is minimum
• if a < 0 then vertex is maximum
here a = 1 > 0 then (3, 0 ) is a minimum
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Answer is 3 seconds
When the bullet reaches the ground, ground being x in graph (and here its s which is = 0)
s = -16t^2 + 48t
s = 0, solve for t
0 = -16t^2 + 48t
0 = t ( -16t + 48)
0 = 16t ( - t + 3)
now you have two equation
0 = 16t and 0 = -t +3 ( you can look at the graph line touches x twice)
0 = 16 t
0 = t ( you know its false, because time = 0)
You are left with
0 = -t + 3
t = 3
It takes 3 seconds for the bullet to return to the ground.
// Hope this helps.
recall from the previous posting, 2⁸ = 256, so that's one way to represent it.
now, another way hmmm