Question

Solve for points. identify the vertex and indicate whether it is max or min.

Answer 1

Answer:

min at (3, 0 )

Step-by-step explanation:

given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

then the x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

y = (x - 3)² = x² - 6x + 9 ← in standard form

with a = 1 and b = - 6 , then

$x_{vertex}$ = - $\frac{-6}{2}$ = 3

substitute x = 3 into the equation for corresponding value of y

y = (3 - 3)² = 0² = 0

vertex = (3, 0 )

• if a > 0 then vertex is minimum

• if a < 0 then vertex is maximum

here a = 1 > 0 then (3, 0 ) is a minimum