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uysha [10]
3 years ago
15

Find the value of x for the question.​

Mathematics
2 answers:
nadya68 [22]3 years ago
7 0

Answer:

x = 5

Step-by-step explanation:

The two angles are congruent because of the Vertical Angles Theorem. Since we now know that they're congruent, we can set up an equation to like this:

15x = 16x - 5

Now that we have an equation, we can solve for x.

First, we subtract 15x from both sides. Now we're left with an equation that should look like this:

0 = x - 5

Now we add 5 to both sides to get our solution. It should look like this.

5 = x

And there's your answer! Hope this helps.

lakkis [162]3 years ago
6 0

Answer:

5

Step-by-step explanation:

Both angles together will equal as they are opposite of each other

therefore

15x=16x-5

15x+5=16x

5=x

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Step-by-step explanation:

The number -1 and 1/3 is directly to the right of -1 and 2/3 because there is a -1/3 difference between them

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Solve for x.  x/4≥−8 <br>1.) x≤−32<br>2.) x≥−2 <br>3. )x≥−32 <br>4.) x≤−2 
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Read 2 more answers
Use the binomial expression (p+q)^n to calculate a binomial distribution with n=5 and p=0.3.(Show all steps)
Helen [10]

Answer:

The binomial in expanded form is (0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}.

Step-by-step explanation:

The Binomial Theorem states that a binomial of the form (a + b)^{n} can be expanded by using the following identity:

(a + b)^{n} = \Sigma \limits^{n}_{k = 0}\,\frac{n!}{k!\cdot (n-k)!}\cdot a^{n-k}\cdot b^{k} (1)

If we know that a = p = 0.3 and n = 5, then the expanded form of the binomial is:

(p+q)^{n} = \frac{243}{100000} + 5\cdot \left(\frac{81}{10000} \right)\cdot q + 10\cdot \left(\frac{27}{1000})\cdot q^{2} + 10\cdot \left(\frac{9}{100} \right)\cdot q^{3} + 5\cdot \left(\frac{3}{10} \right)\cdot q^{4} + q^{5}

(0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}

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3 years ago
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