The number of moles of air present is 0.056 mole
<h3>What is the ideal gas equation?</h3>The ideal gas is one in which molecules do not attract or repel each other.Many gases like oxygen,nitrogen, carbon di oxide can be treated as the ideal gases as particular temperature and pressure.The real gases at high temperature and lower pressure can be treated as ideal gases.
The given data in the question is
Volume = 1.35 L
Pressure (P) = 750 torr
Temperature (T) = 17 °C = 17 + 273 = 290 K
Gas constant (R) = 62.396 L•torr/mol•K
The number of moles (n) =?
How to determine the number of moles:
The number of moles present can be obtained by using the ideal gas equation as illustrated below:
Divide both sides by RT
Hence, the number of moles of air present is 0.056 mole
To learn more about the ideal gas equation follow
Answer : We can produce 125.7 g of .
Explanation : The reaction will be
The molecular mass of is 64.1 g/mol
and molecular mass of is 34.1 g/mol
For every mole of we would need twice of
moles, so for every 3 moles of
we need 16 moles of
Now, we can calculate number of moles
2.61 X (3/16) = 0.49 moles
Here, the molecular mass of is 256.8 g
multiplying it with the number of 0.49 moles we get, 256.8 X 0.49 = 125.7 g of .
Hence, 125.7 g of will be produced.
Answer : The enthalpy change of reaction is -23.9 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given final reaction is,
The intermediate balanced chemical reaction will be,
(1)
(2)
First we will reverse the reaction 1 and multiply equation 2 by 3 then adding both the equation, we get :
(1)
(2)
The expression for final enthalpy is,
Therefore, the enthalpy change of reaction is -23.9 kJ
