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3 years ago

12.00 moles of naclo3 will produce how many grams of O2? (Moles to Grams)

1 answer:

4 0

2NaClO₃ → 2NaCl + 3O₂

mole ratio of NaClO₃ to O₂ is 2 : 3

∴ if moles of NaClO₃ = 12 mol

then moles of O₂ = $\frac{12 mol * 3}{2}$

= 18 mol

Mass of O₂ = mol of O₂ × molar mass of O₂

= 18 mol × 16 g/mol

= 288 g

So I wasn't sure which equation to use since you did not specify so I just used the decomposition reaction. If you should have used another reaction then just follow the same steps and you'll get your answer.

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For+the+reaction+H2+++I2+-+2HI+the+equilibrium+constant,+kc+is+49+at+a+fixed+temperature.+Two+mole+of+hydrogen+and+two+moles+of+

Sonja [21]

Answer : The initial concentration of HI and concentration of HI at equilibrium is, 0.27 M and 0.386 M respectively.

Solution : Given,

Initial concentration of H_2 and I_2 = 0.11 M

Concentration of H_2 and I_2 at equilibrium = 0.052 M

Let the initial concentration of HI be, C

The given equilibrium reaction is,

H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

Initially 0.11 0.11 C

At equilibrium (0.11-x) (0.11-x) (C+2x)

As we are given that:

Concentration of H_2 and I_2 at equilibrium = 0.052 M = (0.11-x)

The expression of K_c will be,

K_c=\frac{[HI]^2}{[H_2][I_2]}

54.3=\frac{(C+2(0.058))^2}{(0.052)\times (0.052)}

By solving the terms, we get:

C = 0.27 M

Thus, initial concentration of HI = C = 0.27 M

Thus, the concentration of HI at equilibrium = (C+2x) = 0.27 + 2(0.058) = 0.386 M

3 0

3 years ago

The percent yield of this reaction is consistently 92.0%. CH4(g) + 4 S(g) → CS2(g) + 2 H2S(g) How many grams of sulfur would be

dybincka [34]

Answer:

132.17 g

Explanation:

The reaction given , in the question is -

CH₄ (g ) + 4 S ( g ) ---> CS₂ ( g ) + 2H₂S ( g )

From the reaction , 4 mole of S is required for the production of 1 mole of CS₂ .

since ,

Moles of CS₂ = given mass of CS₂ / Molecular weight of CS₂

Since ,

the Molecular weight of CS₂ = 76

Given , mass of CS₂ = 72.57 g

Moles of CS₂ = 72.57 / 76 = 0.95 mol

Since ,

The yield is 92.0 % .

Moles of S required = 4 * 0.95 mol / 0.92 = 4.13 moles

Mass of S required = 4.13 * 32 = 132.17 g .

6 0

3 years ago

On the periodic table, the majority of elements are classified as

Roman55 [17]

On the periodic table, the majority of elements are classified as "Metals"

In short, Your Answer would be Option A

Hope this helps!

8 0

3 years ago

Read 2 more answers

Calcula el pH de las siguientes sustancias formadas durante una erupción volcánica:

Virty [35]

Calculate the pH of the following substances formed during a volcanic eruption:

• Acid rain if the [H +] is 1.9 x 10-5

• Sulfurous acid if [H +] = 0.10

• Nitric acid if [H +] = 0.11

<h3>Further explanation </h3>

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.

pH = - log [H⁺]