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adoni [48]
1 year ago
15

According to the bohr model what is the energy of an n=4 electron in a hydrogen atom?

Chemistry
1 answer:
I am Lyosha [343]1 year ago
5 0

According to Bohr's model, the energy of n = 4 electron in a hydrogen atom is 1.3625 × 10⁻¹⁹J

<h3>Bohr's Model of Hydrogen Atom</h3>

According to the postulates given by Bohr, electrons revolve around the nucleus in fixed circular orbits which are called stationary orbits or stationary states.

The energy of electrons in a stationary state is fixed and given by,

E_n = \frac{-2\pi^2me^4}{n^2h^2} Z^2

where, m = mass of electrons = 9.1 x 10⁻³¹ kg

e = charge on electron = 1.602 × 10⁻¹⁹ C

n = no of orbits

h = Planck's constant

Z= atomic number of H-like particles

After calculating all the constants values, we get

E_n= \frac{-2.18 \times 10^-^{18}}{n^2} \times Z^2\\\\E_n= \frac{-2.18 \times 10^-^{18}}{4} \times 1^2

= 0.13625 × 10⁻¹⁸

= 0.13625 × 10⁻¹⁹ J

Hence, the energy of n = 4 electron in a hydrogen atom is 1.3625 × 10⁻¹⁹J

Learn more about Bohr's Model of Hydrogen Atom:

brainly.com/question/20688647

#SPJ4

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Since colloid is a solution, thus it is made up of two parts; its particles and dispersing medium.

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3 years ago
Assuming an efficiency of 49.70%, calculate the actual yield of magnesium nitrate formed from 139.0 g of magnesium and excess co
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Answer:

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8 0
2 years ago
A copper ore containing 4.3 wt% water, 10.3 wt% CuSO, and 85.3 wt% rock is fed to a staged counter current extractor at a rate o
Serga [27]

Answer:

6 stages

Explanation:

Given:

Copper ore contains:

4.3 wt% water

10.3 wt% CuSO₄

85.3 wt% rock

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solution produced is to be 10 wt% copper sulfate

90 wt% water

Now,

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= 0.103 × 11.7

= 1.2051 tons per hour

also,

At each stage 2 tons of solution is collected

therefore,

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= weight of solution × 10 wt% copper sulfate

= 2 tons per hour × 0.1

= 0.2 tons per hour

also,

98% of the CuSO₄ is to be recovered

thus,

the amount of CuSO₄ to be recovered

= 0.98 × CuSO₄ supplied through the feed

= 0.98 × 1.2051 tons per hour

= 1.180998

Therefore,

The number of stages required = \frac{\textup{amount of CuSO₄ to be recovered }}{\textup{CuSO₄ collected in each stage }}

= \frac{\textup{1.180998}}{\textup{0.2}}

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3 years ago
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Answer:

graphite

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Graphite is opaque, a very good lubricant, a good conductor of electricity, and a thermal insulator. Allotropes of carbon are not limited to diamond and graphite, but also include buckyballs (fullerenes), amorphous carbon, glassy carbon, carbon nanofoam, nanotubes, and others.

HOPE IT HELPS :)

PLEASE MARK IT THE BRAINLIEST!

8 0
2 years ago
Can someone help me with number 2?
DanielleElmas [232]

Answer:

Ammonia (NH3)

Explanation:

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