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Phoenix [80]
3 years ago
14

A 1 200-kg car traveling initially at vCi 5 25.0 m/s in an easterly direction crashes into the back of a 9 000-kg truck moving i

n the same direction at vTi 5 20.0 m/s (Fig. P9.22). The velocity of the car immediately after the collision is vCf 5 18.0 m/s to the east. (a) What is the velocity of the truck immediately after the colli
Physics
1 answer:
sukhopar [10]3 years ago
8 0

Answer:

The velocity of the truck after the collision is 20.93 m/s

Explanation:

It is given that,

Mass of car, m₁ = 1200 kg

Initial velocity of the car, v_{Ci}=25\ m/s

Mass of truck, m₂ = 9000 kg

Initial velocity of the truck, v_{Ti}=20\ m/s

After the collision, velocity of the car, v_{Cf}=18\ m/s

Let v is the velocity of the truck immediately after the collision. The momentum of the system remains conversed.

initial\ momentum=final\ momentum

1200\ kg\times 25\ m/s+9000\ kg\times 20\ m/s=1200\ kg\times 18+9000\ kg\times v

210000-21600=9000\ kg\times v

v=20.93\ m/s

So, the velocity of the truck after the collision is 20.93 m/s. Hence, this is the required solution.

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Define work done against friction<br>(helpp)​
77julia77 [94]

Answer:

The work done against friction is the work done on an object that overcomes this frictional force allowing the object to move - it doesn't include any extra work used to accelerate an object for example - only the work used to beat the frictional force.

Explanation:

7 0
4 years ago
What are the advanced warning systems for hurricanes, and how do they work?
Gnesinka [82]

Answer: A hurricane watch is issued 48 hours in advance of the anticipated onset of tropical-storm-force winds in an area

3 0
2 years ago
18. A circuit contains a 10 ohm resistor, a 50 ohm resistor, and an 80 ohm resistor connected in parallel. If you test this circ
lutik1710 [3]

The equivalent resistance is D) 7.55 \Omega

Explanation:

The equivalent resistance of n resistors in parallel is given by the equation:

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+...+\frac{1}{R_n}

For three resistors such as in this problem, the equation becomes

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

where we have the following:

R_1 = 10 \Omega is the resistance of the 1st resistor

R_2 = 50 \Omega is the resistance of the 2nd resistor

R_3 = 80 \Omega is the resistance of the 3rd resistor

Substituting, we find the equivalent resistance:

\frac{1}{R}=\frac{1}{10}+\frac{1}{50}+\frac{1}{80}=0.133 \Omega^{-1}

R=\frac{1}{0.133}=7.55 \Omega

Learn more about resistance:

brainly.com/question/2364338

brainly.com/question/12246020

#LearnwithBrainly

4 0
4 years ago
300 grams of ethanol is heated with 14640 Joules of energy to reach a final temperature of 30 °C. What was the initial temperatu
levacccp [35]

Answer:

10 °C

Explanation:

Applying

q = cm(t₂-t₁)............... Equation 2

Where q = heat energy, c = specific heat of ethanol, m = mass of ethanol, t₁ = initial temperature, t₂ = Final temperature.

Given: c = 2.44 J/g.°C,  m = 300 g, q = 14640 J, t₂ = 30°C

Substitute into equation 2 and solve for t₁

14640 = 2.44×300(30-t₁)

14640 = 732(30-t₁)

732(30-t₁) = 14640

(30-t₁)  = 14640/732

(30-t₁)  = 20

t₁ = 30-20

t₁ = 10 °C

6 0
3 years ago
Read 2 more answers
A sheet of gold leaf has a thickness of 0.125 micrometer. A gold atom has a radius of 174pm. Approximately how many layers of at
Olegator [25]

Answer:

719

Explanation:

Conversion

1 picometer (pm) is equivalent to 1 × 10^{-12} meter

1 micrometer is equivalent to 1 × 10^{-6} meter

To find the number of layers, we divide the overal leaf thickness by the thickness of one atom hence dividing tex]0.125 × 10^{-6}[/tex] meter by 174 × 10^{-12} meter we get that the number of sheets will be as follows

\frac {0.125× 10^{-6}}{174\times 10^{-12}}=718.3908045\approx 719

Therefore, they are approximately 719 sheets

7 0
3 years ago
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