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Yuliya22 [10]
2 years ago
12

THE METHOD TO SOLVE THIS 2 EQUATION IS SUBSTITTUION AND ALGERBRICALLY HERE'S THE EQUATION:

Mathematics
1 answer:
Anon25 [30]2 years ago
3 0

Answer:

x = 3, y = 3

Step-by-step explanation:

x = -5x -18

5x + 18 = -x

6x + 18 = 0

6x = 18

x = 3

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99 + 81 = 9(11 help eeeeeeeeeeeeeeee
Leokris [45]

Answer:

180?

Step-by-step explanation:

3 0
2 years ago
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A small train at an amusement park is carrying passengers. Half of the passengers are 4 years old, 1/10 are 5 years old, 3/10 ar
drek231 [11]
Your answer is 5, because the majority is 5 years old

8 0
3 years ago
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Move two choices to the blanks to correctly complete the sentences.
Pavel [41]

Answer:

(A) There should have been 5 outcomes of HT

(B) The experimental probability is greater than the theoretical probability of HT.

Step-by-step explanation:

Given

S = \{HH,HT,TH,TT\} -- Sample Space

n(S) = 4 --- Sample Size

Solving (a); theoretical outcome of HT in 20 tosses

First, calculate the theoretical probability of HT

P(HT) = \frac{n(HT)}{n(S)}

P(HT) = \frac{1}{4}

Multiply this by the number of tosses

P(HT) * n= \frac{1}{4} * 20

P(HT) * n= 5

<em></em>

Solving (b); experimental probability of HT

Here, we make use of the table

P(HT) = \frac{n(HT)}{n(S)}

P(HT) = \frac{6}{20}

P(HT) = 0.30 ---- Experimental Probability

In (a), the theoretical probability is:

P(HT) = \frac{1}{4}

P(HT) = 0.25 ---- Experimental Probability

By comparison;

0.30 > 0.25

6 0
3 years ago
How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antif
konstantin123 [22]

440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze

<em><u>Solution:</u></em>

Let "x" be the gallons of 80 % antifreeze added

Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze

Final mixture is x + 80

Therefore, we can frame a equation as:

"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze

Thus, we get,

x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %

x \times \frac{80}{100} + 80 \times \frac{15}{100} = (x+80) \times \frac{70}{100}\\\\0.8x + 80 \times 0.15 = (x+80) \times 0.7\\\\0.8x+12 = 0.7x+56\\\\0.8x-0.7x=56-12\\\\0.1x = 44\\\\x = \frac{44}{0.1}\\\\x = 440

Thus 440 gallons of 80 % antifreeze solution must be mixed

4 0
3 years ago
At the zoo the polar bears are fed from 4 kg bucket of a fish day.If each bears eats 3 upon 5 from that bucket what amount of fi
ser-zykov [4K]

Answer:

2400 grams

Step-by-step explanation:

The bears are fed from a 4 kg bucket each day. If the bears eat 3/5 of that bucket, therefore, the amount of fish that the bears eat is:

3 / 5 * 4 = 2.4 kg

Converting this to grams:

1 kg = 1000 g

2.4 kg = 2.4 * 1000 = 2400 grams

The bears feed is 2400 grams

6 0
3 years ago
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