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1 year ago

Please help me (attachment)PLease DO NOT FLAG it appilies to all the rules!

Mathematics

2 answers:

lara31 [8.8K]1 year ago

5 0

9) 46
10) 4
11) 46
12) 5.8
13) 36
14) 34
15) 9
16) 56

Pepsi [2]1 year ago

5 0

9) 46
10) 4
11) 46
12) 5.8
13) 36?
14) 34
15) 9
16) 56

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A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch

ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

Then,

$P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\$

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0

3 years ago

The function ƒ(x) = 2x is vertically translated 5 units down and then reflected across the y-axis. What's the new function of g(

TEA [102]

Answer:

g(x) = -2x - 5

2x becomes -2x as a reflection across the y-axis

add on -5 to shift the function 5 units down

7 0

3 years ago

Find the area of the following kite:

muminat

Answer:64

Step-by-step explanation:

2×2=4

4×2=8

8×8=64

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2 years ago

What number should be added to both sides of the equation to complete the square x^2+8×=4

svp [43]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

I need step by step help with: 3x^1/3 + 2x^2/3 =5

Luba_88 [7]

If you write $y=x^{1/3}$ , you'll notice this is really just a quadratic equation that can be factorized:

$2x^{2/3}+3x^{1/3}-5=0\iff 2y^2+3y-5=0\iff (2y+5)(y-1)=0\iff(2x^{1/3}+5)(x^{1/3}-1)=0$

So you have

$2x^{1/3}+5=0\implies 2x^{1/3}=-5\implies x^{1/3}=-\dfrac52\implies x=-\dfrac{125}8$

and

$x^{1/3}-1=0\implies x^{1/3}=1\implies x=1$

5 0

3 years ago