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ki77a [65]
3 years ago
9

Can someone please help me??

Mathematics
1 answer:
Semmy [17]3 years ago
7 0

since we don't know any of your vocabulary, I might not be using the ones you learned


since we have points A and B and points F(A) and F(B), I think they want us to use the word 'translation'

"The function F(x) translates each point to the right without moving them up or down." would be my description


also the 2 lines are paralell


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Somebody help me out please
Marina86 [1]

Answer:

D

Step-by-step explanation:

7 0
2 years ago
Find the sum of each series, if it exists<br>91 + 85 + 79 + … + (­29)
Natali [406]

Answer:

651.

Step-by-step explanation:

Note: In the given series it should be -29 instead of 29 because 29 cannot be a term of AP whose first term is 91 and common difference is -6.

Consider the given series is

91+85+79+...+(-29)

It is the sum of an AP. Here,

First term = 91

Common difference = 85 - 91 = -6

Last term = -29

nth term of an AP is

a_n=a+(n-1)d

where, a is first term and d is common difference.

-29=91+(n-1)(-6)

-29-91=(n-1)(-6)

\dfrac{-120}{-6}=(n-1)

20=(n-1)

n=20+1=21

Sum of AP is

Sum=\dfrac{n}{2}[\text{First term + Last term}]

Sum=\dfrac{21}{2}[91+(-29)]

Sum=\dfrac{21}{2}[62]

Sum=651

Therefore, the sum of given series is 651.

5 0
2 years ago
Can you guys figure out the linear function for this table, please?
Bess [88]

Answer:

y = 6x + 10

Step-by-step explanation:

This is because the slope is 6 and the y intercept is 10, therefore the answer is y = 6x + 10

5 0
2 years ago
I NEED HELP ASAP(look at the picture for the problem)
Maru [420]

Answer:

M = 1

Step-by-step explanation:

8 0
2 years ago
Q(–1, a) is 4 5 units away from P(3, –2). Find all possible values of a
Natali [406]

Answer:

Step-by-step explanation:

Using the formula for calculating the distance between 2 points.

D = √(x2-x1)²+(y2-y1)²

Given

D = 45 units

The coordinates Q(–1, a) and P(3,2)

45 = √(3-(-1))²+(-2-a)²

45 = √4²+(-2-a)²

45 = √16+(-2-a)²

45² = 16+(-2-a)²

45² = 16+4+4a+a²

45² = 20+4a+a²

a²-4a+20-2025 = 0

a²+4a-2005 = 0

a = -4±√16+4(2005)/2

a = -4±√16+8020/2

a = -4±√8036/2

a =  -4±90/2

a = -4+90/2

a = 86/2

a = 43

The possible values of a is 43

5 0
3 years ago
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