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3 years ago

Find the square meters

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

5 0

Answer:

17 square meters

Step-by-step explanation:

Begin by finding the area of the whole rectangle without the cut out. The area is A = l*w = 4*5 = 20.

Now find the area of the cut out and subtract it from 20.

A = l*w = 3*1 = 3

20 -3 = 17

The area of the figure is 17.

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Use a diagram words, and angle relationships to explain your answer

tankabanditka [31]

Answer:

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8 0

3 years ago

Find the equation of a sphere if one of its diameters has endpoints: (-9, -12, -6) and (11, 8, 14).

baherus [9]

Answer:

Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is $(x-1)^{2}+(y+2)^{2}+(z-4)^{2} = 30$ .

Step-by-step explanation:

There are two kew parameters for a sphere: Center ( $h$ , $k$ , $s$ ) and Radius ( $r$ ). The radius is the midpoint of the line segment between endpoints. That is:

$C(x,y,z) = \left(\frac{-9+11}{2},\frac{-12+8}{2},\frac{-6+14}{2} \right)$

$C(x,y,z) = (1,-2,4)$

The radius can be found by halving the length of diameter, which can be determined by knowning location of endpoints and using Pythagorean Theorem:

$r = \frac{1}{2}\cdot \sqrt{(-9-11)^{2}+(-12-8)^{2}+(-6-14)^{2}}$

$r = 10\sqrt{3}$

The general formula of a sphere centered at (h, k, s) and with a radius r is:

$(x-h)^{2}+(y-k)^{2}+(z-s)^{2} = r^{2}$

Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is $(x-1)^{2}+(y+2)^{2}+(z-4)^{2} = 30$ .

8 0

3 years ago

jacks tent is shaped like an isosceles triangle. the height of the tent measures 7 feet and the diagonal side measures 9 feet. f

abruzzese [7]

Answer:

$8\sqrt{2}\ ft$

Step-by-step explanation:

see the attached figure to better understand the problem

Remember that

An isosceles triangle has two equal sides and two equal interior angles

In the isosceles triangle ABC

Applying the Pythagorean Theorem

Let

b ----> the length of the tents base

$9^2=7^2+(b/2)^2$

$(b/2)^2=9^2-7^2$

$(b^2/4)=32$

$b^2=128\\\\b=\sqrt{128}\ ft$

simplify

$b=8\sqrt{2}\ ft$

3 0

3 years ago

A cylindrical pillers has a diameter of 56 cm and is of 35 m high there are 16 pillers around the building find the cost of pain

viktelen [127]

Answer:

Answer:

Total cuŕved surface area of the pillars = 985.6m²Total cost of painting = Rs.5420.8

Explanation:

Given,

A cylindrical pillar with dimènsions,

r(radius) = 56/2 = 28cm. [ Since d = r/2]h(height) = 35m

There are 16 such pillars. Find the cost of paiñting the the curved surface area of all pillars 5.50/m²

Conversion of the dimensioñs in same units.

Radius = 28cm

= 28 ÷ 100 [Since 1m = 100]

= 0.28m

Cuŕved surface area of the pillar is given by,

→ 2πrh

Where,

Taking ‘π’ as 22/7

→ 2*(22/7)*(0.28)*(35)

5 0

2 years ago

The temperature yesterday morning was 9° below zero. Write<br><br> the temperature as an integer.

True [87]

-9 , because it is below zero

3 0

3 years ago

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