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nikklg [1K]
2 years ago
5

Part B

Mathematics
1 answer:
ziro4ka [17]2 years ago
3 0

The linear equation that has a slope of -7 and crosses the x-axis at (3, 0) is:

y =  -7x + 21

<h3>How to find the linear equation?</h3>

A general linear equation is:

y = a*x +b

Where a is the slope and b is the y-intercept.

The slope must be equal to the limit found in part a, and you say that it is equal to -7, so the slope is -7. And for how is written the problem, I understand that it crosses the x-axis at x = 3.

Then we will have:

y = -7*x + b

Such that, when x = 3, y = 0, then:

0 = -7*3 + b

21 = b

Then the linear equation is y = -7x + 21

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

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Part C: Find the distance from B to E and from P to E. Show your work. (4 points)
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Answer:

BE = 294.23 ft

PE = 259.62 ft

Step-by-step explanation:

Quadrilateral CPRG is a parallelogram.

CP || GR

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\angle BCG \cong \angle BPE  (Alternate \: \angle 's) \\\angle GBC \cong \angle EBP  (Vertical \: \angle 's) \\\therefore \triangle BCG \sim \triangle BPE  (AA \: postulate) \\\\\therefore \frac{BE}{BG}  =\frac{PE}{GC} =\frac{BP}{BC}...(csst)\\\\\therefore \frac{BE}{425}  =\frac{PE}{375} =\frac{225}{325}\\\\\therefore \frac{BE}{425}  =\frac{PE}{375} =\frac{9}{13}\\\\\therefore \frac{BE}{425} =\frac{9}{13}\\\\BE =\frac{9\times 425}{13}\\\\BE =\frac{3,825}{13}\\\\BE = 294.23\: ft \\\\\&\\\frac{PE}{375} =\frac{9}{13}\\\\PE =\frac{9\times 325}{13}\\\\PE =\frac{3,375}{13}\\\\PE = 259.615385 \\\\PE = 259.62 \: ft\\\\

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The mean of her first five quiz scores is found by adding the scores together and dividing by 5:

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