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Zigmanuir [339]
2 years ago
10

Show the two (neutral) organic starting materials that would be used to synthesize the following ketone by a hydroxide mediated

crossed‑aldol reaction
Chemistry
1 answer:
pav-90 [236]2 years ago
3 0

Show the two (neutral) organic starting materials that would be used to synthesize the following ketone by a hydroxide mediated crossed‑aldol reaction the product formed is alpha-beta unsaturated carbonyl compound.

<h3>What is the Aldol-condensation ?</h3>

The condensation response among distinctive molecules of an aldehyde or ketone in a protic solvent which includes water or alcohol constitutes the crossed aldol response. When condensation is among distinctive carbonyl compounds, it's far referred to as crossed aldol condensation.

Applying the retrosynthetic evaluation technique, the systems of the beginning substances are decided via way of means of the usage of the bottom catalyzed for the crossed aldol mechanism. The beginning substances are aldehyde and ketone compounds that react with every different to present the goal molecule.

Read more about the aldehyde :

brainly.com/question/1792281

#SPJ4

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Write a balanced equation and determine Eº for each of the following cells: a) Cr Cr3+||Ni2+|Ni b) (CF|C1,||MnO | Mn?)
Alexxx [7]

Answer:

Explanation:

Step 1: Write both half reactions

Cr / Cr3+ : oxidation  Cr(s) → Cr3+ + 3e-  

Ni2+ / Ni : reduction Ni2+ +2e- → Ni

Step 2: Balance reactions and look up the standard potential for the  half-reactions

2(Cr → Cr3+ + 3e-)    E° ox = 0.74 V

3(Ni2+ +2e- → Ni)     E° red = -0.25 V

2Cr + 3Ni2+ +6e- → 2Cr3+ +6e- + 3Ni

E°cell = E° red + E° ox  = -0.25 + 0.74  = 0.49

E = E ° − 0.0257 V /n * ln Q  = E ° − 0.0257 V /n  *l n [ C r 3 + ]/ [ N i 2 + ]

With E° = 0.49 V

b)

Step 1: Write both half reactions

MnO4-/ Mn2+ (redution)   MnO4-  +8H+ +5e- ⇔ Mn2+ +4H2O

Cf ⇔ Cf2+ +2e-   (oxidation)   Cf ⇔ Cf2+ +2e-

Step 2: Balance reactions and look up the standard potential for the  half-reactions

MnO4-  +8H+ +10-e- ⇔ Mn2+ +4H2O    E° = 1.51 V

5Cf ⇔ 5 Cf2+ +10e-        E° =2.12 V

2 MnO4- + 16H+ + 5Cf ⇔ 2Mn2+ + 8H2O + 5Cf2+

E°cell = E° red + E° ox  = 1.51 + 2.12  = 3.63 V

E = E ° − 0.0257 V /n * ln Q  = E ° − 0.0257 V /n  *l n [ C f2 + ]/ [ Mno4- ]

With E° =3.63 V

7 0
2 years ago
For a species with a diploid number of 26, indicate how many chromosomes will be present in the somatic nuclei of individuals th
Sedbober [7]

Answer:

Haploid - 13

Triploid - 39

Tetraploid - 52

Trisomic - 27

Monosomic - 25

Explanation:

A haploid organism has half the chromosome number of a diploid version, hence 26/2 = 13

A triploid organism has 3 sets of a haploid chromosomes, hence 13 x 3 = 39

A tetraploid is double of a diploid, 26 x 2 = 52

Trisomic organisms have one extra chromosome in addition to the normal diploid. Hence 26 + 1 = 27

Monosomic organism has one less chromosome than the normal diploid. Hence 26 - 1 = 25

6 0
2 years ago
What is a vocab word for newton's second law?
olga nikolaevna [1]

Answer:

proportional. having a constant ratio. Second law: A body of mass m subject to a net force F undergoes an acceleration a that has the same direction as the force and a magnitude that is directly proportional to the force and inversely proportional to the mass, i.e., unbalanced.

Explanation:

hope it's help

8 0
2 years ago
Read 2 more answers
How much energy (in J) is lost when a sample of iron with a mass of 26.4 g cools from 74.0 ∘C to 26.0 ∘C?
Greeley [361]

Answer:

Q=-526.6J

Explanation:

Hello,

In this case, for the computation of the energy loss when the cooling process is carried out, we use the shown below equation:

Q=mCp\Delta T

Whereas we need the mass, specific heat and change in temperature of iron within the process. Thus, the only value we need is the specific heat that is 0.444 J/(g°C), therefore, we compute the heat loss:

Q=26.4g*0.444\frac{J}{g\°C}*(26.0\°C-74.0\°C)\\ \\Q=-526.6J

Negative sign points out the loss due to the cooling.

Regards.

8 0
3 years ago
FeS2 + 5 O2 2Fe2 + 4SO2 How many moles of FeO are formed from 0.57 moles of O2?
bagirrra123 [75]

Answer:

0.228 mol FeO

Explanation:

                                 2FeS2 + 5 O2----> 2FeO + 4SO2

from reaction                           5 mol       2 mol

given                                       0.57 mol    x

x = 0.57*2/5 = 0.228 mol FeO

3 0
3 years ago
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