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Zigmanuir [339]
2 years ago
10

Show the two (neutral) organic starting materials that would be used to synthesize the following ketone by a hydroxide mediated

crossed‑aldol reaction
Chemistry
1 answer:
pav-90 [236]2 years ago
3 0

Show the two (neutral) organic starting materials that would be used to synthesize the following ketone by a hydroxide mediated crossed‑aldol reaction the product formed is alpha-beta unsaturated carbonyl compound.

<h3>What is the Aldol-condensation ?</h3>

The condensation response among distinctive molecules of an aldehyde or ketone in a protic solvent which includes water or alcohol constitutes the crossed aldol response. When condensation is among distinctive carbonyl compounds, it's far referred to as crossed aldol condensation.

Applying the retrosynthetic evaluation technique, the systems of the beginning substances are decided via way of means of the usage of the bottom catalyzed for the crossed aldol mechanism. The beginning substances are aldehyde and ketone compounds that react with every different to present the goal molecule.

Read more about the aldehyde :

brainly.com/question/1792281

#SPJ4

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what modifications to either or both of the half-cell reactions would kim need to make if she wanted to use them to produce equa
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We have to add the both half cell equations and eliminate the number of electrons lost/gained.

<h3>What modification must Kim make to the equations?</h3>

The term redox reaction is a type of reaction that occurs when an electron  is lost or gained in a reaction system. We can see that in this reaction, zinc looses two electron which are gained by copper.

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7 0
1 year ago
Draw an energy diagram for an endothermic and exothermic reaction and label the diagram ​
just olya [345]
Energy diagram for and endothermic and exothermic reaction

5 0
3 years ago
Read 2 more answers
TRUE or FALSE
andriy [413]

Answer:

1. true

2. false

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Explanation:

5 0
2 years ago
Butane (C4 H10(g), mc031-1.jpgHf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , mc031-2.jpgHf = –393.5 kJ/
ankoles [38]

The balanced chemical equation for the combustion of butane is:

2C_{4}H_{10}(g) +13 O_{2}(g)-->8CO_{2}(g)+10H_{2}O(g)

ΔH_{reaction}^{0} = Σn_{products}ΔH_{f}^{0}_{(products)}-Σn_{reactants}ΔH_{f}^{0}_{(reactants)}

                         = [{8*(-393.5kJ/mol)}+{10*(-241.82kJ/mol)}]-[{2*(-125.6kJ/mol)}+13*(0 kJ/mol)}]=[-3148kJ/mol+(-2418.2kJ/mol)]-[(-251.2kJ/mol)+0]

                      = -5315 kJ/mol

Calculating the enthalpy of combustion per mole of butane:

1mol C_{4}H_{10}*( \frac{-5315kJ}{2mol C_{4}H_{10} })=-2657.5 \frac{kJ}{molC_{4}H_{10}}

Therefore the heat of combustion per one mole butane is -2657.5 kJ/mol

Correct answer: -2657.5 kJ/mol

6 0
2 years ago
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