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mario62 [17]
4 years ago
13

Treatment of 2-hexanone with naoch2ch3 followed by ch3br affords compound x (c7h14o) as the major product. x shows a strong abso

rption in the ir spectrum at 1713 cm-1, and its 1h nmr data is given below. what is the structure of x?

Chemistry
1 answer:
VashaNatasha [74]4 years ago
8 0
The given ketone when reacted with base gave enolate, the enolate formed due to loss of methylene proton next to carbonyl group. Enolate when treated with methyle Bromide gave alpha substituted product. 

Strong absorption around 1713 cm⁻¹ in IR spectrum confirms the presence of Carbonyl group.

The product along with ¹H-NMR values is given below,

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What is the Bronsted acid of H2PO4- + OH-. ---- HPO42- + H2O?​
RoseWind [281]

Answer:

The bronsted- Lowry acid is H₂PO₄⁻

Explanation:

Bronsted-Lowry acid  donates a proton (H⁺)

H₂PO₄⁻ + OH⁻ → HPO₄²⁻ + H₂O

In the reaction above, H₂PO₄⁻ is donating the proton to OH⁻ resulting in H₂O and the deprotonated species. This makes it a bronsted-Lowry acid.

7 0
3 years ago
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Why might a scientist repeat an experiment if she did not make a mistake in the first one? A) Scientists who repeat experiments
9966 [12]

Answer:

The correct answer is B) it helps to ensure the result are consistent and repeatable.

Explanation:

Scientist generally repeat an experiment if he or she did not make a mistake in the first one to compare the results of two experiment, if there is no difference in the result or values obtainted from the observation of two experiment. he or she become sure that experiment was done in a right way because if there is some error made when experiment was carried out then the result of two same experiment would be different.

3 0
3 years ago
What is the equation for the average?
s2008m [1.1K]

Explanation:

The equation for the average is: (sum of all data values/ (total number of data values)

4 0
3 years ago
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1. A 225-L barrel of white wine has an initial free SO2 concentration of 22 ppm and a pH of 3.70. How much SO2 (in grams) should
Alexandra [31]

Answer:

The appropriate answer is "9.225 g".

Explanation:

Given:

Required level,

= 63 ppm

Initial concentration,

= 22 ppm

Now,

The amount of free SO₂ will be:

= Required \ level -Initial \ concentration

= 63-22

= 41 \ ppm

The amount of free SO₂ to be added will be:

= 41\times 225

= 9225 \ mg

∵ 1000 mg = 1 g

So,

= 9225\times \frac{1}{1000}

= 9.225

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"9.225 g" should be added.

3 0
3 years ago
A student Increases the temperature of a 417 cubic centimeter balloon from 278 K to 231 K. Assuming constant pressure what shoul
WITCHER [35]
Initial Conditions:
Volume= v1= 417 cm³
Temperature= T1 = 278 K
 
Final Conditions:
Temperature= T2 = 231K
Volume = v2 =?

Use the general gas equation;

                                        P1*v1/T1 =  P2*v2/T2
As, the temperature is constant;
 So,
                                               v1/T1 = v2/T2
                                              417/278 = v2/231
                                                  v2= 346.5 cm³                                           
5 0
3 years ago
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