Treatment of 2-hexanone with naoch2ch3 followed by ch3br affords compound x (c7h14o) as the major product. x shows a strong abso
rption in the ir spectrum at 1713 cm-1, and its 1h nmr data is given below. what is the structure of x?
1 answer:
The given ketone when reacted with base gave enolate, the enolate formed due to loss of methylene proton next to carbonyl group. Enolate when treated with methyle Bromide gave alpha substituted product.
Strong absorption around 1713 cm⁻¹ in IR spectrum confirms the presence of Carbonyl group.
The product along with ¹H-NMR values is given below,
Strong absorption around 1713 cm⁻¹ in IR spectrum confirms the presence of Carbonyl group.
The product along with ¹H-NMR values is given below,
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Answer:
The appropriate answer is "9.225 g".
Explanation:
Given:
Required level,
= 63 ppm
Initial concentration,
= 22 ppm
Now,
The amount of free SO₂ will be:
=
=
=
The amount of free SO₂ to be added will be:
=
=
∵ 1000 mg = 1 g
So,
=
=
Thus,
"9.225 g" should be added.