Treatment of 2-hexanone with naoch2ch3 followed by ch3br affords compound x (c7h14o) as the major product. x shows a strong abso
rption in the ir spectrum at 1713 cm-1, and its 1h nmr data is given below. what is the structure of x?
1 answer:
The given ketone when reacted with base gave enolate, the enolate formed due to loss of methylene proton next to carbonyl group. Enolate when treated with methyle Bromide gave alpha substituted product.
Strong absorption around 1713 cm⁻¹ in IR spectrum confirms the presence of Carbonyl group.
The product along with ¹H-NMR values is given below,
Strong absorption around 1713 cm⁻¹ in IR spectrum confirms the presence of Carbonyl group.
The product along with ¹H-NMR values is given below,
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Answer:
Three hydrogen atoms to form PH₃.
Explanation:
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In this case, since the elements belonging to the nitrogen family (N, P, As, Sb and Bi) show five valence electrons, because there are five electrons at their outer shell, it is clear that if phosphorous bonds with hydrogen, it is going to require the same amount of oxygen atoms (3) because elements having five valence electrons need 3 bonds in order to attain the octet (5+3=8).
Therefore the compound would be:
Which is phosphine.
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