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2 years ago

HELP ME THIS IS 1 MONTH OVER DUE PLS HURRY

Chemistry

2 answers:

dsp732 years ago

6 0

1,3, and 4 are true

AVprozaik [17]2 years ago

4 0

1false
2false
3true
4true

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a chemist wishes to mix some pure acid with some water to produce 16L of a solution that is 30% acid how much pure acid and how

Aloiza [94]

Answer: The volume of acid and water that must be mixed will be 4.8 L and 11.2 L

Explanation:

We are given:

Volume of mixture = 16 L

Percent of acid present = 30 %

Calculating the percentage of acid present in the mixture:

$\Rightarrow 16\times \frac{30}{100}=4.8L$

The mixture is made entirely of acid and water.

Volume of acid in the mixture = 4.8 L

Volume of water in the mixture = 16 - 4.8 = 11.2 L

Hence, the volume of acid and water that must be mixed will be 4.8 L and 11.2 L

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3 years ago

Methyl tertiary-butyl ether (MTBE) is an organic compound that has been in use since the late 1970s. Read the article to learn m

tamaranim1 [39]

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2 years ago

Based on what basis the elements had been arranged

salantis [7]

Answer:

The increase in the atomic number

6 0

2 years ago

If 3.31 moles of argon gas occupies a volume of 100 L what volume does 13.15 moles of argon occupy under the same temperature an

kumpel [21]

Answer:

397 L

Explanation:

Recall the ideal gas law:

$\displaystyle PV = nRT$

If temperature and pressure stays constant, we can rearrange all constant variables onto one side of the equation:

$\displaystyle \frac{P}{RT} = \frac{n}{V}$

The left-hand side is simply some constant. Hence, we can write that:

$\displaystyle \frac{n_1}{V_1} = \frac{n_2}{V_2}$

Substitute in known values:

$\displaystyle \frac{(3.31 \text{ mol})}{(100 \text{ L})} = \frac{(13.15\text{ mol })}{V_2}$

Solving for V₂ yields:

$\displaystyle V_2 = \frac{(100 \text{ L})(13.15)}{3.31} = 397 \text{ L}$

In conclusion, 13.15 moles of argon will occupy 397* L under the same temperature and pressure.

(Assuming 100 L has three significant figures.)

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1 year ago

What happens at the cathode in an electrolytic cell? (Answer is reduction)

melisa1 [442]

Answer:

At the cathode in an electrolytic cell, ions in the surrounding solution are reduced into atoms, which precipitate or plate out on to the solid cathode. The anode is where oxidation takes place, and the cathode is where reduction takes place.

Explanation:

7 0

2 years ago

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