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liberstina [14]
3 years ago
5

HELP ME THIS IS 1 MONTH OVER DUE PLS HURRY

Chemistry
2 answers:
dsp733 years ago
6 0
1,3, and 4 are true
AVprozaik [17]3 years ago
4 0
1false
2false
3true
4true
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What is the final temperature of a 27.2-gram wooden block that starts at 23.4°C and loses 759 joules of energy? The specific hea
sattari [20]

T = final temperature  of the block

T₀ = initial temperature of the block = 23.4 °C

Q = energy lost  from the wooden block = - 759 J

c = specific heat capacity of wood = 1.716 J/(g  °C)

m = mass of the wooden block = 27.2 g

Heat lost from the block is given as

Q = m c (T - T₀)

inserting the values

- 759 = (27.2) (1.716) (T - 23.4)

T = 7.1 °C

6 0
4 years ago
Is this a redox reaction? give evidence (many points plz answer)<br> 2Mg + CO2 → 2MgO + C
Aleonysh [2.5K]

Answer:

\boxed{yeah}

Explanation:

CO_2 \:  is \: reduced \: to→C \: by \:  2M_g \: (the \: reducing \: agent): while \\ 2M_g \: is \: oxydized \: to→2M_gO \: by \:  CO_2 \: (the \: oxydizing \: agent)

6 0
3 years ago
Put these steps of solar
kupik [55]

Answer:

3-1-5-2-4

Explanation:

scientists believe that the solar system was formed when some star had its explosion and due to its explosion there were waves generated in the space thus squeezing clouds and dust eventually gravity pulling everything together forming solar nebula. the clouds spin faster and faster thus making it into a thin disk and also the cloud becoming hotter and dense thus forming stars.

5 0
3 years ago
Read 2 more answers
Explain how you determined which water use was larger.
aksik [14]

Answer:

Which ever item has more water inside of it

Explanation:

4 0
4 years ago
Suppose that 3.33 g of acetone at 25.0 °C condenses on the surface of a 44.0-g block of aluminum that is initially at 25 °C. If
jeyben [28]

Answer:

68.6 °C

Explanation:

From conservation of energy, the heat lost by acetone, Q = heat gained by aluminum, Q'

Q = Q'

Q = mL where Q = latent heat of vaporization of acetone, m = mass of acetone = 3.33 g and L = specific latent heat of vaporization of acetone = 518 J/g

Q' = m'c(θ₂ - θ₁) where m' = mass of aluminum = 44.0 g, c = specific heat capacity of aluminum = 0.9 J/g°C, θ₁ = initial temperature of aluminum = 25°C and θ₂ = final temperature of aluminum = unknown

So, mL = m'c(θ₂ - θ₁)

θ₂ - θ₁ = mL/m'c

θ₂ = mL/m'c + θ₁

substituting the values of the variables into the equation, we have

θ₂ = 3.33 g × 518 J/g/(44.0 g × 0.9 J/g°C) + 25 °C

θ₂ = 1724.94 J/(39.6 J/°C) + 25 °C

θ₂ = 43.56 °C + 25 °C

θ₂ = 68.56 °C

θ₂ ≅ 68.6 °C

So, the final temperature (in °C) of the metal block is 68.6 °C.

5 0
3 years ago
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