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Alex787 [66]
2 years ago
14

The population of Country A is about 1,070,000 and the population of

Mathematics
1 answer:
Andrei [34K]2 years ago
5 0

Answer:

i do not know

Step-by-step explanation:

I just want the points

sorry

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Well we would know if you told us the ingridients
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Here's a graph of a linear function. Write the
zmey [24]

Answer:

  y = -2x -5

Step-by-step explanation:

The line crosses the y-axis at -5. So, b = -5.

It goes down 2 units for each 1 unit to the right, so has a slope of ...

  m = rise/run = -2/1 = -2

__

The slope-intercept form of the equation of a line is ...

  y = mx +b      where m is the slope and b is the y-intercept

For the slope and y-intercept shown, the equation is ...

  y = -2x -5

5 0
3 years ago
an agent sold a land with 3% commission and he gave Rs9215000 to the owner find the amount of commission​
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Answer:

While the average real estate agent commission hovers around 5% to 6%, depending on where you live, the total cost of selling tends to be higher.

8 0
2 years ago
Evaluate. −27/125−−−−√3 A.-9/25 B.-3/5 C.9/25 D.3/5
Vladimir79 [104]
\sqrt[3]{\dfrac{-27}{125}} = -\sqrt[3]{\left(\dfrac{3}{5}\right)^{3}}=\dfrac{-3}{5}

The appropriate choice appears to be ...
   B. -3/5
7 0
3 years ago
Read 2 more answers
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
3 years ago
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