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2 years ago

Which number line shows the solution to the inequality 8x – 9 < –41?

Mathematics

1 answer:

lora16 [44]2 years ago

7 0

Answer:

Step-by-step explanation:

In the inequality, you want to simplify it to get x on one side, and the numeric values on the other.

So, moving 9 to the other side, you get, 8x<-32

Then, you can divide by 8 on both sides to get x alone.

You get, x<-4.

From this, we can see that it should be an open dot at -4, and pointing to the left.

So, the correct number line is A.

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A hairstylist schedules 1/4 hour to trim a customers hair and 1/6 hour to style the customers hair. the hairstylist plans to wor

Lana71 [14]

To make it simple make them all the same fraction

6/24 to trim 4/24 to style and she wants to work for 80/24 hours for 5 days

if each appointment she wants to take 6/24 to trim and 4/24 to style then every appointment will take 10/24 of an hour.

she wants to do 80/24 so she can do 8 appointments a day if each take 10/24

8 appointments a day 5 days a week

8x5= 40

3 0

3 years ago

Evaluate x+3y when x=2, y-3

AlekseyPX

Answer:

-7

Step-by-step explanation:

x+3y

Let x =2 and y = -3

2 +3(-3)

2 -9

-7

6 0

3 years ago

Read 2 more answers

Please help with this algebra :)

Dahasolnce [82]

I am gonna go for D is the answer.

8 0

3 years ago

Find the price-demand equation for a particular brand television when the demand is 20 TVs per week at $150 per TV, given that t

Alina [70]

Answer:

~ $150=50e^{-0.01()20}$

~ $p(100)=\$127.7$

Step-by-step explanation:

From the question we are told that:

Price of 20TVs per week $P_{20}=\$150$

Marginal price-demand function $p'(x)=-0.5e-0.01x$

Generally the The Marginal price function is mathematically given by

$p'(x)=-0.5e^{-0.01x}$

$p(x)=\int-0.5e^{-0.01x}$

$p(x)=50e^{-0.001x}+C$

Therefore the equation when the demand is 20 TVs per week at $150 per TV

$150=50e^{-0.01()20}$

Giving

$p(x)=50e^{-0.01x}+150-50e^{-0.01(20)}$

Therefore the Price when the demand is 100 TVs per week

$p(100)=50e^{-0.01(100)}+150-50e^{-0.01(20)}$

$p(100)=\$127.7$

7 0

2 years ago

I really need help with this one please

natka813 [3]

The distance from the sun is option 2 5.59 astronomical units.

Step-by-step explanation:

Step 1; To solve the question we need two variables. P which represents the number of years a planet takes to complete a revolution around the Sun. This is given as 13.2 years in the question so P = 13.2 years. The other variable is the distance between the planet and the sun in astronomical units. We need to determine the value of this using the given equation.

Step 2; So we have to calculate the value of 'a' in Kepler's equation. But the exponential power $\frac{3}{2}$ is on the variable we need to find so we multiply both the sides by an exponential power of $\frac{2}{3}$ to be able to calculate 'a'.

P = $a^{\frac{3}{2} }$ , $P^{\frac{2}{3} }$ = $a^{\frac{3}{2}*\frac{2}{3} }$ , $P^{\frac{2}{3} }$ = a, $13.2^{\frac{2}{3} }$ = a = 5.58533 astronomical units.

Rounding it over to nearest hundredth we get 5.59 astronomical units.

6 0

3 years ago