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Debora [2.8K]
3 years ago
5

How to solve 5y+23=6y+4y-17

Mathematics
1 answer:
rjkz [21]3 years ago
7 0

Answer:

y=8

Step-by-step explanation:

<u>hope it helps!!
</u>

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What is the some need help????​
snow_tiger [21]

The sum formula for a geometric sequaence is:

sum(n) = a1(1-r^n)/1-r

Where n is the number of terms, a1 is the first term and r is the common ratio:

s(8) = 3(1-1/2^8) / (1-1/2)

s(8) = 3(1-1/256) / 1/2

s(8) = 2 253/256 / 1/2

s(8) = 765/128

The answer is C.

5 0
4 years ago
Pleaseee help I’m struggling so hard
ivanzaharov [21]

Answer:

-3

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
All of the following expressions are equivalent except.___ 2+m m+2 m-(-2) -2-m
Pachacha [2.7K]

Answer:

\Huge \boxed{-2-m}

Step-by-step explanation:

2 + m

Rewrite with variable first.

m + 2

m + 2

Can’t be simplified further.

m - (-2)

Distribute negative sign.

m + 2

-2-m

Rewrite with variable first.

-m - 2

The last expression is not equivalent to m+2.

4 0
3 years ago
(5x-12)+(3x+30)+(48)
skelet666 [1.2K]

Answer:

8x+66

Step-by-step explanation:

8 0
3 years ago
Find two values for k such that the trinomial x2 – 7x + k can be factored over the integers. Explain your reasoning.
vova2212 [387]

Answer:

1) For a = 1: b = 6 and k = 6, 2) For a = 3: b = 4 and k = 12

Step-by-step explanation:

The polynomial y = x^{2} - 7\cdot x + k is a second-order polynomial of the form (x-a)\cdot (x-b) = x^{2}-(a+b)\cdot x + a\cdot b. By direct comparison, we construct the following system of equations:

a + b = 7 (1)

a\cdot b = k (2)

By (1) we know that there are a family of pairs such that the system of equations is satisfied. Let suppose that both a and b are integers. We assume two arbitrary integers for a:

1) a = 1

b = 7 - a

b = 6

a\cdot b = k

k = (6)\cdot (1)

k = 6

2) a = 3

b = 7 - a

b = 4

a\cdot b = k

k = (3)\cdot (4)

k = 12

6 0
3 years ago
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