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hodyreva [135]
3 years ago
11

Solve the equation 4/9y=8/3

Mathematics
1 answer:
ahrayia [7]3 years ago
3 0
Multiply by 9/4 to get y=6.
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What is the solution, you can round to the nearest tenth
AnnZ [28]

Answer:

The top one is 1

Step-by-step explanation:

8 0
2 years ago
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Help pleaseeee ??????!!!!! I choosed the Death Valley one
disa [49]
1.) C(t) = -0.30(t - 12)^2 + 40
for t = 12: C(12) = -0.30(12 - 12)^2 + 40 = -0.30(0)^2 + 40 = 40°C
For t = 24: C(24) = -0.30(24 - 12)^2 + 40 = -0.30(24 - 12)^2 + 40 = -0.30(12)^2 + 40 = -0.30(144) + 40 = -43.2 + 40 = -3.2°C

4.) F(t) = 9/5 C(t) + 32
for C(t) = 40°C: 9/5 (40) + 32 = 72 + 32 = 104°F
for C(t) = -3.2°C: 9/5(-3.2) + 32 = -5.76 + 32 = 26.24°F

5.) F(t) = 9/5 C(t) + 32 = 9/5 (-0.30(t - 12)^2 + 40) + 32 = -0.54(t - 12)^2 + 72 + 32 = -0.54(t - 12)^2 + 104
5 0
3 years ago
PQR is a triangle. PR = 13 cm, PQ = 12 cm and angle QPR = 30°<br> Calculate the length of QR.
Deffense [45]

Answer:

6.55 cm

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. Types of triangles are isosceles, acute, scalene, obtuse, right and equilateral triangle.

Cosine rule is used to show the relationship between sides and angles of a triangle. If a, b, and c are sides of a triangle, while A, B, and C are angles opposite to the corresponding sides. Then:

c² = a² + b² - 2ab*cos(C)

Given that PR = 13 cm, PQ = 12 cm and angle QPR = 30°, hence:

QR² = PR² + PQ² - 2(PR)(PQ)cos(∠QPR)

QR² = 13² + 12² - 2(13)(12)cos(30) = 169 + 144 - 270

QR² = 43

QR = 6.55 cm

3 0
2 years ago
What is the measure of ACB in O below?​
Nezavi [6.7K]

Answer:

A

Step-by-step explanation:

The central angle is equal to the arc that subtends it , then

arc AB = 30°

arc ACB = 360° - 30° = 330° → A

7 0
3 years ago
Solve for x. Assume that lines are diameters?
Delicious77 [7]
360 - 20 + 2x = 360
340 + 2x = 360
2x = 20
x = 10
5 0
3 years ago
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